哈夫曼树,c++。假设用于通信的电文仅由8个字母组成,
答案:1 悬赏:20
解决时间 2021-03-03 09:43
- 提问者网友:回忆在搜索
- 2021-03-02 15:30
哈夫曼树,c++。假设用于通信的电文仅由8个字母组成,
最佳答案
- 二级知识专家网友:琴狂剑也妄
- 2021-03-02 16:50
#include "stdio.h"
#include "conio.h"
main( )
{
long a,b,c,d,e,x;
scanf("%ld",&x);
a=x/10000;
b=x%10000/1000;
c=x%1000/100;
d=x%100/10;
e=x%10;
if (a!=0) printf("there are 5, %ld %ld %ld %ld %ld\n",e,d,c,b,a);
else if (b!=0) printf("there are 4, %ld %ld %ld %ld\n",e,d,c,b);
else if (c!=0) printf(" there are 3,%ld %ld %ld\n",e,d,c);
else if (d!=0) printf("there are 2, %ld %ld\n",e,d);
else if (e!=0) printf(" there are 1,%ld\n",e);
getch();
}
#include "conio.h"
main( )
{
long a,b,c,d,e,x;
scanf("%ld",&x);
a=x/10000;
b=x%10000/1000;
c=x%1000/100;
d=x%100/10;
e=x%10;
if (a!=0) printf("there are 5, %ld %ld %ld %ld %ld\n",e,d,c,b,a);
else if (b!=0) printf("there are 4, %ld %ld %ld %ld\n",e,d,c,b);
else if (c!=0) printf(" there are 3,%ld %ld %ld\n",e,d,c);
else if (d!=0) printf("there are 2, %ld %ld\n",e,d);
else if (e!=0) printf(" there are 1,%ld\n",e);
getch();
}
我要举报
如以上问答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息,可以点下面链接进行举报!
大家都在看
推荐资讯