已知xy=2,x-y=3,求(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y的值。
答案:3 悬赏:60
解决时间 2021-03-22 11:47
- 提问者网友:北故人
- 2021-03-22 08:10
已知xy=2,x-y=3,求(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y的值。
最佳答案
- 二级知识专家网友:转身后的回眸
- 2021-03-22 08:37
(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y
=x^2-y^2-y^2-3x^2+xy
=-2(x^2+Y^2)+xy
=-2(x^2+Y^2-2xy)-4xy+xy
=-2(x-y)^2-3xy
=-2*3^2-3*2
=-24
=x^2-y^2-y^2-3x^2+xy
=-2(x^2+Y^2)+xy
=-2(x^2+Y^2-2xy)-4xy+xy
=-2(x-y)^2-3xy
=-2*3^2-3*2
=-24
全部回答
- 1楼网友:错过的是遗憾
- 2021-03-22 10:12
(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/(2y) =x^2-y^2-y^2+x^2+y^2-2xy-3x^2+xy =-x^2-y^2-xy =-(x^2+y^2+xy-3xy+3xy) =-(x-y)^2-3xy =-9+6 =-3
- 2楼网友:偏爱自由
- 2021-03-22 10:06
已知xy=2,x-y=3,
(x+y)(x-y)-y²-(6x²y-2xy²)/2y
=x²-y²-y²-3x²+xy
=-2(x²+y²-2xy)-3xy
=-2(x-y)²-3xy
=-2*3²-3*2
=-24
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