SQL笔试试题
答案:2 悬赏:0
解决时间 2021-01-10 00:46
- 提问者网友:斑駁影
- 2021-01-09 09:31
SQL笔试试题
最佳答案
- 二级知识专家网友:想偏头吻你
- 2021-01-09 10:17
select ACCOUNT
,sum(RENT),sum().... from USERLIST a ,CHARGE b where a.TELEPHONE
=b.TELEPHONE(+)
group by a.ACCOUNT
上面是oracle用的
通用的是
select ACCOUNT
,sum(RENT),sum().... from USERLIST a left join CHARGE b on a.TELEPHONE
=b.TELEPHONE
group by a.ACCOUNT
,sum(RENT),sum().... from USERLIST a ,CHARGE b where a.TELEPHONE
=b.TELEPHONE(+)
group by a.ACCOUNT
上面是oracle用的
通用的是
select ACCOUNT
,sum(RENT),sum().... from USERLIST a left join CHARGE b on a.TELEPHONE
=b.TELEPHONE
group by a.ACCOUNT
全部回答
- 1楼网友:封刀令
- 2021-01-09 11:00
select account,count(rent),sum(rent),nvl(sum(fee01),0),nvl(sum(fee02),0),nvl(sum(fee03),0),nvl(sum(fee04),0)
from USERLIST, CHARGE
and userlist.telephone=change.telephone(+)
group by account
order by 1;
from USERLIST, CHARGE
and userlist.telephone=change.telephone(+)
group by account
order by 1;
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