求解答C++问题

求解答C++问题

你说的是main函数中的return？ return 0; 是告诉操作系统你的程序运行正常，而其他数字是代表了一个错误号。但是有时我们可以不用这么准确，错误了返回1就可以了。但是在驱动编程中最好把各个错误号对应好：
下面是返回值的具体意义：

EPERM Operation not permitted 1
ENOENT No such file or directory 2
ESRCH No such process 3
EINTR Interrupted function 4
EIO I/O error 5
ENXIO No such device or address 6
E2BIG Argument list too long 7
ENOEXEC Exec format error 8
EBADF Bad file number 9
ECHILD No spawned processes 10
EAGAIN No more processes or not enough memory or maximum nesting level reached 11
ENOMEM Not enough memory 12
EACCES Permission denied 13
EFAULT Bad address 14
EBUSY Device or resource busy 16
EEXIST File exists 17
EXDEV Cross-device link 18
ENODEV No such device 19
ENOTDIR Not a directory 20
EISDIR Is a directory 21
EINVAL Invalid argument 22
ENFILE Too many files open in system 23
EMFILE Too many open files 24
ENOTTY Inappropriate I/O control operation 25
EFBIG File too large 27
ENOSPC No space left on device 28
ESPIPE Invalid seek 29
EROFS Read-only file system 30
EMLINK Too many links 31
EPIPE Broken pipe 32
EDOM Math argument 33
ERANGE Result too large 34
EDEADLK Resource deadlock would occur 36
EDEADLOCK Same as EDEADLK for compatibility with older Microsoft C versions 36
ENAMETOOLONG Filename too long 38
ENOLCK No locks available 39
ENOSYS Function not supported 40
ENOTEMPTY Directory not empty 41
EILSEQ Illegal byte sequence 42
STRUNCATE String was truncated 80
希望能解决您的问题。

给你提个醒吧，以后写程序就按照这种格式写，比较清晰，还有就是提问的时候最好把问题标明，还有就是把程序功能写明，这样方便解答的人能更快地解答

#include<stdio.h>  struct {   char name[10];  int score;//这里改成整形的数，不是数组，这里用数组显然是不对的。 }temp,stu[]={{"lihong",0},{"wangjian",0},{"zhaoming",0}}; void main() {  int i,j,x=0;  for(i=1; i<=8;i++)  {         printf("\n输入第%d门课的成绩:\n",i);     for(j=0;j<3;j++)     {    printf("姓名:%s  成绩为:",stu[j].name);    scanf("%d",&x);    stu[j].score+=x;     }      }  for ( i=0; i<2; i++)     for ( j=i+1; j<3; j++)     if (stu[i].score<stu[j].score)     {         temp=stu[j];     stu[j]=stu[i];     stu[i]=temp;    }  for   ( i=0; i<3; i++)  { //这里加花括号，不然你的输出就一个   printf( "\n  姓名:%s 总成绩:%d\n",stu[i].name,stu[i].score);  } }