js 距离某一时间点时间是多少实现代码
答案:2 悬赏:20
解决时间 2021-03-06 15:04
- 提问者网友:但未伤到心
- 2021-03-06 08:39
js 距离某一时间点时间是多少实现代码
最佳答案
- 二级知识专家网友:零负荷的放任
- 2021-03-06 10:07
var date1=new Date(); //开始时间<br><br>var date2=new Date(); //结束时间<br><br>var date3=date2.getTime()-date1.getTime() //时间差的毫秒数<br><br>------------------------------<br><br>//计算出相差天数<br><br>var days=Math.floor(date3/(24*3600*1000))<br><br>//计算出小时数<br><br>var leave1=date3%(24*3600*1000) //计算天数后剩余的毫秒数<br><br>var hours=Math.floor(leave1/(3600*1000))<br><br>//计算相差分钟数<br><br>var leave2=leave1%(3600*1000) //计算小时数后剩余的毫秒数<br><br>var minutes=Math.floor(leave2/(60*1000))<br><br>//计算相差秒数<br><br>var leave3=leave2%(60*1000) //计算分钟数后剩余的毫秒数<br><br>var seconds=Math.round(leave3/1000)<br><br>alert(" 相差 "+days+"天 "+hours+"小时 "+minutes+" 分钟"+seconds+" 秒")
全部回答
- 1楼网友:转身→时光静好
- 2021-03-06 10:24
<%
function countdown(dtmwhenends)
dtmnow = now()
if dtmwhenends > dtmnow then
intdiffsr = datediff("s", dtmnow, dtmwhenends)
intdiffmr = intdiffsr \\ 60
intdiffhr = intdiffmr \\ 60
intdiffdr = intdiffhr \\ 24
intdiffsa = intdiffsr - (intdiffmr * 60)
intdiffma = intdiffmr - (intdiffhr * 60)
intdiffha = intdiffhr - (intdiffdr * 24)
intdiffda = intdiffdr
if intdiffda = 1 then
strdays = "天"
else
strdays = "天"
end if
strtimeleft = strtimeleft & intdiffda & strdays
if intdiffha = 1 then
strhours = "小时"
else
strhours = "小时"
end if
strtimeleft = strtimeleft & intdiffha & strhours
if intdiffma = 1 then
strminutes = "分"
else
strminutes = "分"
end if
strtimeleft = strtimeleft & intdiffma & strminutes
if intdiffsa = 1 then
strseconds = "秒"
else
strseconds = "秒"
end if
strtimeleft = strtimeleft & intdiffsa & strseconds
end if
countdown = replace(strtimeleft,"-","")
end function
nnn=countdown("2008-8-24 12:23:34")
response.write("消息发布于:"&nnn&"前")
%>
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