c++ operator

答案:2 悬赏:60

解决时间 2021-02-27 13:25

提问者网友：傀儡离开
2021-02-26 16:20

定义一个class > my_int

下面提供MAIN函数参数，哪位高手帮我把CLASS完成？
int main(void){
my_int a, b, c;
my_int plus, minus, product, divide, asso;
cin >> a;
cin >> b;
cin >> c;
plus = a+b;
minus = a-b;
product = a*b;
divide = a/b;
asso = a*b-c;
cout << "a = " << a << "b = " << b <<"c = " << c << endl;
cout << "a + b = " << plus;
cout << "a - b = " << minus;
cout << "a * b = " << product;
cout << "a / b = " << divide;
cout << " a * b - c = " << asso;
return 0;
}

运行后屏幕输出：

3
2
1
a=3
b=2
c=1
a+b=5
a-b=1
a*b=6
a/b=1
a*b-c=5

最佳答案

二级知识专家网友：气场征服一切
2021-02-26 16:45

给你一段代码，已经测试过的了，给我最佳啊

#include
#include
using namespace std;
class my_int
{
public:
my_int(){};
my_int (double m)
{
n = m;
}
my_int operator + (const my_int& a);
my_int operator - (const my_int& a);
my_int operator * (const my_int& a);
my_int operator / (const my_int& a);
friend ostream & operator << (ostream &,my_int &);
friend istream & operator >> (istream &,my_int &);

double n;
};

my_int my_int::operator + (const my_int& a)
{
return my_int(n + a.n);
}
my_int my_int::operator - (const my_int& a)
{
return my_int(n - a.n);
}
my_int my_int::operator * (const my_int& a)
{
return my_int(n * a.n);
}
my_int my_int::operator / (const my_int& a)
{
return my_int(n / a.n);
}
ostream & operator << (ostream &output,my_int &p)
{

cout < return output;
}
istream & operator >> (istream &input,my_int &p)
{

cin >>p.n;
return input;
}

int main()
{
my_int a, b, c;
my_int plus, minus, product, divide, asso;
cin >> a;
cin >> b;
cin >> c;
plus = a+b;
minus = a-b;
product = a*b;
divide = a/b;
asso = a*b-c;
cout << "a = " << a << "b = " << b <<"c = " << c << endl;
cout << "a + b = " << plus;
cout << "a - b = " << minus;
cout << "a * b = " << product;
cout << "a / b = " << divide;
cout << " a * b - c = " << asso;
system("Pause");
return 0;
}

全部回答

1楼网友：错过的是遗憾
2021-02-26 17:44

operator和运算符号连起来就看做是函数名调用的时候直接写运算符就可以了和一般函数没区别 =============================== 可以有也可以没有返回值不过有一种特例，比如把某一种类型自动转换成另一种类型 struct a { int c; operator int* () //将 a类型转换成int*类型 { return &c; } }; void main() { a a; a.c=5; int *p; p=a;//调用了自动转换，一般的写法应该是 p=&(a.c), cout<<*p<

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