python中如何得到一组循环的数

比如 有1234 得到2341 3412 4123

def cycle(num):        #产生某一数字的所有循环数
strNum = str(num)
length = len(strNum)
cycle_all = []
for i in range(length):
number = int(strNum[i:] + strNum[:i])
cycle_all.append(number)
return cycle_all
if __name__ == '__main__':
for i in cycle(1234):
print i,

Easy ;) a = [1,2,3,4,5] # put in whatever you like for i in range(len(a)): print a[i:]+a[:i] I recommend you have more reading about the python list object, you'll be surprised of what it can give you

foo = "1234" for i in range(len(foo)):     print(foo[i:] + foo[:i])

def cycle_list(num): s=str(num) return [int(s[i:]+s[:i]) for i in range(len(s))] cycle_list(1234567) #[1234567, 2345671, 3456712, 4567123, 5671234, 6712345, 7123456]

直接有内置函数可以找出list中的最大值 >>> a = [1,3,5,7,9] >>> print max(a) 9完全没必要使用while循环啊