用配方求2X²+3X=0和3X²-1=6X 要有过程 急···

2x²+3x=0

x²+3x+（3/2）²=0+(3/2)²

（x+3/2）²=9/4

x+3/2=±3/2

x=±3/2-3/2

x1=0,x2=-3

3x²-1=6x

3x²-1-6x=0

3x²-6x-1=0

x²-2x=1

x²-2x+1=1+1

(x-1）²=2

x-1=±√2

x=±√2+1

x1=√2+1，x2=-√2+1

注：√表示根号。

2(x²+3/2x)=0

2[x²+3/2x+(3/4)²]-(3/4)²×2=0

(x+3/4)²=(3/4)²

x=0

3x²-6x-1=0

3(x²-2x)=1

x²-2x=1/3

x²-2x+1=4/3

(x-1)²=4/3

x-1=±2根号3/3

x=±2根号3/3+1

1.) 2(x^2+3x/2)=0

2(x+3/4)^2=9/8

(x+3/4)^2=9/16

x+3/4=3/4 x+3/4=-3/4

x1= .. x2=..

2) 3x^2-6x-1=0

3(x^2-2x)-1=0

3(x-1)^2=4

(x-1)^2=4/3

x-1=（2根号3）/3 x-1=负（2根号3）/3

x1=... x2=...

2X²+3X=0 2(x^ +3x/2+ 9/16)=9/8 (x+3/4)^ =9/16 x=0 or x=-3/2

3X²-1-6X =0 3(X-1)²=4 x=1+-2√ 3/3 x=1-2√ 3/3 or x=1+2√ 3/3

1 2X²+3X=0

(2x+3)x=0

x=0或x=-3/2

2 3X²-1=6X

3X²-6x-1=0

3(x-1)²=4

x=1+2根号3/3 或x=1-2根号3/3