c语言编写数字记忆游戏

用C语言编写一个数字记忆游戏 满足以下条件：
1.输入要记忆的数字 位数
2.输入完成后 会出现3个 相应位数的数字
3.这3个数字 再1秒钟后消失
4.输入 文字 和符号时 提示程序错误
5.输入刚才出现 过的 3个数字
6.3次输入的 机会，数字输入正确则继续游戏，3次机会全错 则提示游戏是否继续
7.输入Q或者q时 程序结束

我写这类交互式的小程序代码一般都比较丰满，试试看吧XD：

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

#define TIME 1
#define N 3

int ws;
int num[N];

void clear()
{
while(getchar() != '\n');
}

int weishu()
{
char c;
while(1) {
printf("请输入位数(结束Q/q):");

if(scanf("%d", &ws)) {
if(ws >= 1 && ws <= 5)
break;
}
else if((c = getchar()) == 'q' || c == 'C')
return 0;
else
printf("输入错误!请重试.\n");
clear();
}
clear();
return 1;
}

int play()
{
int i, a, b, n;
int in[N];

switch(ws) {
case 1:a = 0, b = 10;break;
case 2:a = 10, b = 89;break;
case 3:a = 100, b = 899;break;
case 4:a = 1000, b = 8999;break;
case 5:a = 10000, b = 89999;break;
}

n = 0;
for(i = 0; i < N; ++i)
n += printf("%d ", num[i] = rand()%b+a);

clock_t now = clock();
while((clock() - now) / CLOCKS_PER_SEC < TIME);

i = n;
while(i--)
putchar('\b');
printf("%*c", n, ' ');
i = n;
while(i--)
putchar('\b');

b = N;
while(b) {
printf("请输入:");
for(i = 0; i < N && scanf("%d", &in[i]); ++i);
if(i < N) {
printf("输入有误!请重试.\n");
clear();
continue;
}

if(b > 0) {
for(i = 0; i < N; ++i)
if(in[i] != num[i]) {
if(b > 1)
printf("输入错误, 你还有%d次机会:\n", b-1);
break;
}
if(i == N)
return 1;
}
b--;
}
return 0;
}

终于写好了 写的比较粗糙 #include <stdio.h> #include <Stdlib.h> #include <windows.h> #include <time.h> const int arrsize=3; int main() { int seed,arr[arrsize],rem[arrsize],i,tag=0,wrong=0; char choice[2],answer; begin: printf("输入位数1-5 输入q/Q结束:"); scanf("%s",&choice); srand(time(NULL)); if(choice[0]=='q'||choice[0]=='Q') exit(0); fflush(stdin); seed=atoi(choice); if(seed>5||seed<1) { printf("输入错误\n");goto begin; } switch(seed) { case 1: for(i=0;i<3;i++) arr[i]=rand()%9+1; break; case 2: for(i=0;i<3;i++) arr[i]=rand()%99+1; break; case 3: for(i=0;i<3;i++) arr[i]=rand()%999+1; break; case 4: for(i=0;i<3;i++) arr[i]=rand()%9999+1; break; case 5: for(i=0;i<3;i++) arr[i]=rand()%99999+1; break; } printf("记忆数字如下\n"); for(i=0;i<3;i++) printf("%d ",arr[i]); Sleep(1000); system("cls"); printf("\n输入你要记忆的数字 按空格键分开\n"); for(i=0;i<3;i++) { scanf("%d",&rem[i]); if(rem[i]==arr[i]); else { tag=1;break; } } if(tag==0) printf("记忆正确\n"); else { printf("记忆错误\n");wrong++; } if(wrong>3) { printf("你已经错误超过3次了,继续游戏y/n"); answer=getchar(); if(answer=='n') exit(0); } goto begin; system("pause"); }

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
static char *question[]={"多出各一半","闭着口,却在笑","五口人说话",
"一来就有学生","学上段,会下段","挖西边,补东边"};
static char *answer[]={"岁","哈","语","尝","扑"};

static char *inspi[]={"差一点！你一定行的！","努力！请再试一次 ！","差一点！你一定行的!","差一点！你一定行的!","差一点！你一定行的"};
int main()
{
char input[20]="";
int i=0,j=0;

for (i=0;i<7;)
{

while (true)
{
printf("%s:\n",question[i]);
scanf("%s",input);

if (strcmp(input,answer[i])==0)//字符串比较
{
if (i<6)
{
system("cls");//清屏，如果你的vc编译这句不过就去掉。。有的电脑用不了跟vc版本有关
printf("你太有才了！\n");
}
else
printf("恭喜你闯关成功!\n");

i++;
break;
}
else
{
system("cls");//清屏，如果你的vc编译这句不过就去掉。。有的电脑用不了跟vc版本有关
printf("%s\n",inspi[i]);
}
}

}

}

#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { char ch; int i, m, r[3], u[3], c; clock_t t; srand((unsigned)time(NULL)); do { while(1) { printf("请输入要记忆数字的位数，结束程序请输入Q或q："); fflush(stdin); ch = getchar(); if(ch == 'Q' || ch == 'q' || '1' <= ch && ch <= '5') break; else printf("输入错误！\n"); } if(ch == 'Q' || ch == 'q') break; ch -= '0'; m = 1; for(i = 1; i < ch; i++) m *= 10; for(i = 0; i < 3; i++) printf("%d ", r[i] = rand() % (m * 9) + m); t = clock(); while(clock() - t < CLOCKS_PER_SEC); for(i = 0; i < (ch + 1) * 3; i++) printf("\b"); for(i = 0; i < (ch + 1) * 3; i++) printf(" "); for(i = 0; i < (ch + 1) * 3; i++) printf("\b"); c = 0; do { for(i = 0; i < 3; i++) if(scanf("%d", &u[i]) != 1) { printf("程序出错！\n"); fflush(stdin); i = -1; } if(r[0] == u[0] && r[1] == u[1] && r[2] == u[2]) break; c++; } while(c < 3); if(c < 3) ch = 'y'; else { printf("是否继续游戏？"); fflush(stdin); ch = getchar(); } } while(ch == 'Y' || ch == 'y'); return 0; }