如何把复杂的数学表达式在matlab中表示出来
答案:1 悬赏:0
解决时间 2021-11-06 17:34
- 提问者网友：孤山下
- 2021-11-06 08:01
如何把复杂的数学表达式在matlab中表示出来
最佳答案
- 二级知识专家网友：鸠书
- 2021-11-06 08:32
此题无显示解的。
程序如下：e如果是自然对数的底，则 e=exp(1);
syms r u d g y w e
solve(-r*u*(cos(d+u)*cos(40*g)*cos(g)*sin(y)*w*cos(y)-sin(d+u)*sin(g)*cos(y)*w*sin(y)-r*u*40*w*cos(y)-w*sin(g)*cos(d+u)*cos(40*g)*e*cos(y)^2-w*cos(g)*sin(d+u)*cos(40*g)*e+w*cos(g)*sin(d+u)*cos(40*g)*e*cos(y)^2-cos(d+u)*cos(g)*40*w*sin(y)-sin(d+u)*cos(y)^2*cos(g)*w*e+sin(y)*w*cos(g)*sin(d+u)*sin(40*g)+cos(d+u)*cos(y)^2*sin(g)*w*e-sin(y)*w*sin(g)*cos(d+u)*sin(40*g)-r*u*cos(40*g)*w-sin(d+u)*sin(g)*40*w*sin(y)-r*u*cos(y)^2*w-cos(d+u)*cos(g)*cos(y)*w*sin(y)+w*sin(g)*cos(d+u)*cos(40*g)*e+sin(d+u)*cos(40*g)*sin(g)*sin(y)*w*cos(y)+r*u*cos(40*g)*w*cos(y)^2)==0,u)
程序如下：e如果是自然对数的底，则 e=exp(1);
syms r u d g y w e
solve(-r*u*(cos(d+u)*cos(40*g)*cos(g)*sin(y)*w*cos(y)-sin(d+u)*sin(g)*cos(y)*w*sin(y)-r*u*40*w*cos(y)-w*sin(g)*cos(d+u)*cos(40*g)*e*cos(y)^2-w*cos(g)*sin(d+u)*cos(40*g)*e+w*cos(g)*sin(d+u)*cos(40*g)*e*cos(y)^2-cos(d+u)*cos(g)*40*w*sin(y)-sin(d+u)*cos(y)^2*cos(g)*w*e+sin(y)*w*cos(g)*sin(d+u)*sin(40*g)+cos(d+u)*cos(y)^2*sin(g)*w*e-sin(y)*w*sin(g)*cos(d+u)*sin(40*g)-r*u*cos(40*g)*w-sin(d+u)*sin(g)*40*w*sin(y)-r*u*cos(y)^2*w-cos(d+u)*cos(g)*cos(y)*w*sin(y)+w*sin(g)*cos(d+u)*cos(40*g)*e+sin(d+u)*cos(40*g)*sin(g)*sin(y)*w*cos(y)+r*u*cos(40*g)*w*cos(y)^2)==0,u)
我要举报
如以上问答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
大家都在看
推荐资讯