2道C语言题目
答案:3 悬赏:80
解决时间 2021-03-08 00:46
- 提问者网友:了了无期
- 2021-03-07 06:59
2道C语言题目
最佳答案
- 二级知识专家网友:西风乍起
- 2021-03-07 08:19
#include
#define N 10
void invert(int *s,int i,int j)
{ int t;
if(i {
t=*(s+i);
*(s+i)=*(s+j);
*(s+j)=t;
invert(s,i+1,j-1);
}
}
void main()
{ int a[N],i;
for(i=0;i scanf("%d",&*(a+i));
invert(a,0,N-1);
for(i=0;i printf("%d",a[i]);
printf("\n");
}
///////////////////////////////////
#include
#include
#define N 80
int fun( char *s)
{
int count=0, i=0;
int flag = 0;
while(s[i] != '\0') {
if(flag==0 && s[i]>='a' && s[i]<='z') {
count++; flag = 1;
}
else if (flag ==1 && s[i] ==' ')
{
flag = 0;
}
i++;
}
return count;
}
void main()
{ char line[N];
int num=0;
printf("Enter a string :\n");
gets(line);
num=fun(line);
printf("The number of word is : %d\n\n",num);
//NONO();
}
#define N 10
void invert(int *s,int i,int j)
{ int t;
if(i
t=*(s+i);
*(s+i)=*(s+j);
*(s+j)=t;
invert(s,i+1,j-1);
}
}
void main()
{ int a[N],i;
for(i=0;i
invert(a,0,N-1);
for(i=0;i
printf("\n");
}
///////////////////////////////////
#include
#include
#define N 80
int fun( char *s)
{
int count=0, i=0;
int flag = 0;
while(s[i] != '\0') {
if(flag==0 && s[i]>='a' && s[i]<='z') {
count++; flag = 1;
}
else if (flag ==1 && s[i] ==' ')
{
flag = 0;
}
i++;
}
return count;
}
void main()
{ char line[N];
int num=0;
printf("Enter a string :\n");
gets(line);
num=fun(line);
printf("The number of word is : %d\n\n",num);
//NONO();
}
全部回答
- 1楼网友:猎心人
- 2021-03-07 11:13
int fun(char *s)
{int i,k=0;
for(i=0;s[i]!='\0';i++)
{if(s[i]>='0'&&s[i]<='9')k++;}
return k;
{int i,k=0;
for(i=0;s[i]!='\0';i++)
{if(s[i]>='0'&&s[i]<='9')k++;}
return k;
- 2楼网友:低音帝王
- 2021-03-07 09:56
int fun(char *s)
{
int count, i=0, j;
int flag = 0;
while(s[i] != '\0') {
if(flag==0 && s[i]>='a' && s[i]<='z') {
count++; flag = 1;
}
else if (flag ==1 && s[i] = ' ') {
flag = 0;
}
i++;
}
return count;
}
{
int count, i=0, j;
int flag = 0;
while(s[i] != '\0') {
if(flag==0 && s[i]>='a' && s[i]<='z') {
count++; flag = 1;
}
else if (flag ==1 && s[i] = ' ') {
flag = 0;
}
i++;
}
return count;
}
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