DOS批处理命令中FOR /R命令的问题

批处理文件中用for /R D:\站点\SPDataQuality %%G in (.) do @echo %%G得到一组目录路径，如下
D:\站点\SPDataQuality\.
D:\站点\SPDataQuality\.kde\.
D:\站点\SPDataQuality\.kde\Autostart\.
D:\站点\SPDataQuality\jpgraph\.
D:\站点\SPDataQuality\jpgraph\docs\.
D:\站点\SPDataQuality\jpgraph\docs\chunkhtml\.
D:\站点\SPDataQuality\jpgraph\docs\chunkhtml\example_src\.
D:\站点\SPDataQuality\jpgraph\docs\chunkhtml\images\.
D:\站点\SPDataQuality\jpgraph\docs\classref\.
D:\站点\SPDataQuality\jpgraph\src\.
D:\站点\SPDataQuality\jpgraph\src\barcode\.
D:\站点\SPDataQuality\jpgraph\src\barcode\demoapp\.
D:\站点\SPDataQuality\jpgraph\src\barcode\examples\.
D:\站点\SPDataQuality\jpgraph\src\Examples\.
D:\站点\SPDataQuality\jpgraph\src\fonts\.
D:\站点\SPDataQuality\jpgraph\src\lang\.
D:\站点\SPDataQuality\jpgraph\src\themes\.
D:\站点\SPDataQuality\others\.
这些路径都是绝对路径，通过什么办法可以把这些都变成相对路径了，也就是说把"D:\站点\"变成".\"列出来？

假设你的这些路径放在1.txt中，在当前目录下，新建一个批处理，代码如下
@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%a in (1.txt) do (
set old=%%a
set new=!old:D:\站点=.!
echo !new!>>2.txt
)

你好！ @echo off setlocal enabledelayedexpansion set p=D:\站点\SPDataQuality for /R %p% %%G in (.) do ( set x=%%G set x=!x:%p%=.! echo !x!) pause 打字不易，采纳哦！