帮帮忙，能不能给我 基于C语言的FIR滤波器设计的程序代码（包括CMD，C,ASM)，谢谢了 真的很急！！！

帮帮忙，能不能给我 基于C语言的FIR滤波器设计的程序代码（包括CMD，C,ASM)，谢谢了 真的很急！！！

#include"math.h"
void firwin(n,band,fln,fhn,wn,h)
int n,band,wn;
double fln,fhn,h[];
{int i,n2,mid;
double s,pi,wc1,wc2,beta,delay;
double window();
beta=0.0;
if(wn==7)
{printf("input beta parameter of Kaiser window(2scanf("%1f",&beta);
}
pi=4.0*atan(1.0);
if((n%2)==0)
{n2=n/2+1;
mid=1;
}
else
{n2=n/2;
mid=0;
}
delay=n/2.0;
wc1=2.0*pi*fln;
if(band>=3) wc2=2.0*pi*fhn;
switch(band)
{case 1:
{for(i=0;i<=n2;i++)
{s=i-delay;
h[i]=(sin(wc1*s)/(pi*s))*window(wn,n+1,i,beta);
h[n-i]=h[i];
}
if(mid==1) h[n/2]=wc1/pi;
break;
}
case 2:
{for(i=0;i<=n2;i++)
{s=i-delay;
h[i]=(sin(pi*s)-sin(wc1*s))/(pi*s);
h[i]=h[i]*window(wn,n+1,i,beta);
h[n-i]=h[i];
}
if(mid==1) h[n/2]=1.0-wc1/pi;
break;
}
case 3:
{for(i=0;i{s=i-delay;
h[i]=(sin(wc2*s)-sin(wc1*s))/(pi*s);
h[i]=h[i]*window(wn,n+1,i,beta);
h[n-i]=h[i];
}
if(mid==1)h[n/2]=(wc2-wc1)/pi;
break;
}
case 4:
{for(i=0;i<=n2;i++)
{s=i-delay;
h[i]=(sin(wc1*s)+sin(pi*s)-sin(wc2*s))/(pi*s);
h[i]=h[i]*window(wn,n+1,i,beta);
h[n-i]=h[i];
}
if(mid==1)h[n/2]=(wc1+pi-wc2)/pi;
break;
}
}
}
static double window(type,n,i,beta)
int i,n,type;
double beta;
{int k;
double pi,w;
double kaiser();
pi=4.0*atan(1.0);
w=1.0;
switch(type)
{case 1:
{w=1.0;
break;
}
case 2:
{k=(n-2)/10;
if(i<=k)
w=0.5*(1.0-cos(i*pi/(k+1)));
break;
}
case 3:
{w=1.0-fabs(1.0-2*i/(n-1.0));
break;
}
case 4:
{w=0.5*(1.0-cos(2*i*pi/(n-1)));
break;
}
case 5:
{w=0.54-0.46*cos(2*i*pi/(n-1));
break;
}
case 6:
{w=0.42-0.5*cos(2*i*pi/(n-1))+0.08*cos(4*i*pi/(n-1));
break;
}
case 7:
{w=kaiser(i,n,beta);
break;
}
}
return(w);
}
static double kaiser(i,n,beta)
int i,n;
double beta;
{
double a,w,a2,b1,b2,beta1;
double bessel0();
b1=bessel0(beta);
a=2.0*i/(double)(n-1)-1.0;
a2=a*a;
beta1=beta*sqrt(1.0-a2);
b2=bessel0(beta1);
w=b2/b1;
return(w);
}
static double bessel0(x)
double x;
{int i;
double d,y,d2,sum;
y=x/2.0;
d=1.0;
sum=1.0;
for(i=1;i<=25;i++)
{d=d*y/i;
d2=d*d;
sum=sum+d2;
if(d2}
return(sum);
}
这是窗函数法的，当然还有其他的比如切比雪夫，零相位滤波什么的，我也在研究，不是很懂哈