这个C#里画五角星的函数，高手解释一下，谢谢

protected override void OnPaint(PaintEventArgs args)
{
Graphics grfx = args.Grphics;

int cx = 300;
int cy = 160;

Point[] apt = new Point[5];
for (int i = 0; i< apt.Length; i++)
{
double dAngle = (i * 0.8 - 0.5) * Math.PI;
apt[i] = new Point((int)(cx * (0.25 + 0.24 * Math.Cos(dAgngle))),(int)(cy * (0.5 + 0.48 * Math.Sin(dAngle))));
}

grfx.FillPolygon(new SolidBrush(Color.Red),
apt,
FillMode.Winding);
}

apt[i] = new Point((int)(cx * (0.25 + 0.24 * Math.Cos(dAgngle))),(int)(cy * (0.5 + 0.48 * Math.Sin(dAngle))))
这一步看不懂

不是坐标点看不懂，是这个算法不懂，0.25,0.24这些算法是怎么得到？

apt[i] = new Point((int)(cx * (0.25 + 0.24 * Math.Cos(dAgngle))),(int)(cy * (0.5 + 0.48 * Math.Sin(dAngle))))

分解开来，是：
new Point(x,y);
x = (int)(cx * (0.25 + 0.24 * Math.Cos(dAgngle)))
0.24乘以dAgngle的COS值，加上0.25，再把结果乘以cx，最后把运算结果转换成int类型
y = (int)(cy * (0.5 + 0.48 * Math.Sin(dAngle)))
0.48乘以dAgngle的SIN值，加上0.5，再把结果乘以cy，最后把运算结果转换成int类型

试试: void mydraw(graphics g,point center,int radius){ point[] pts = new point[5]; //获取五角星5个顶点 pts[0] = new point(center.x,center.y - radius); pts[1] = rotate72(pts[0],center); pts[2] = rotate72(pts[1],center); pts[3] = rotate72(pts[2],center); pts[4] = rotate72(pts[3],center); //简单地拉5条线 pen pen = new pen(new solidbrush(color.blue)); g.drawline(pen,pts[0],pts[2]); g.drawline(pen,pts[0],pts[3]); g.drawline(pen,pts[1],pts[3]); g.drawline(pen,pts[1],pts[4]); g.drawline(pen,pts[2],pts[4]); } //旋转72 private point rotate72(point pt,point center){ int x = (int)(center.x + (pt.x - center.x) * math.cos(72.0 * math.pi/180) - (pt.y - center.y) * math.sin(72.0 * math.pi/180)), y = (int)(center.y + (pt.x - center.x) * math.sin(72.0 * math.pi/180) + (pt.y - center.y) * math.cos(72.0 * math.pi/180)); return new point(x,y); } 这样画出来的五角星是中间有五条线的，如果你想画的是中间没有五条线，看看上面的代码自己就可以搞定了。