数学问题~~~~~~~~
- 提问者网友:冰点阿弟
- 2021-04-26 20:18
(5) (-3/5)*3/5+9/25*(-24)
(6) (1/2004-1)(1/2003-1)(1/2002-1)......(1/1000-1)
- 二级知识专家网友:不服输的倔强
- 2021-04-26 21:56
(5)(-3/5)*3/5+9/25*(-24)=-9/25+(9/25)*(-24)=(9/25)(-1-24)=-9
(6)因为从999到2003共1005个数
所以(1/2004-1)(1/2003-1)(1/2002-1)......(1/1000-1)
=(-2003/2004)(-2002/2003)(-2001/2002)....(-999/1000)
=[(-1)^1005](2003/2004)(2002/2003)(2001/2002)......*(999/1000)
=-999/2004
- 1楼网友:努力只為明天
- 2021-04-27 01:15
(5)原式=-9/25+9/25(-24)=9/25(-1-24)=9/25*(-25)=-9
(6)原式=(-2003/2004) (-2002/2003)(-2001/2002) ....... (-999/1000)
=-(2003/2004 * 2002/2003 ........999/1000)
=-999/2004
- 2楼网友:你好陌生人
- 2021-04-27 00:47
(5) (-3/5)*3/5+9/25*(-24)=-9/25+(9/25)*(-24)=(9/25)(-1-24)=-9 (6) (1/2004-1)(1/2003-1)(1/2002-1)......(1/1000-1)
=(-2003/2004)(-2002/2003)(-2001/2002)....(-999/1000)
=[(-1)^2005](1/2004)(2003/2003)(2002/2002)......*(1000/1000)*999
=-999/2004
- 3楼网友:留下所有热言
- 2021-04-26 23:46
(1)=-9/25+9/25*(-24)
=9/25*(-24-1)
=9/25*(-25)
=-9
(2)=(-2003/2004)(-2002/2003)(-2001/2002).....(-999/1000)
=-999/2004
- 4楼网友:安稳不如野
- 2021-04-26 23:33
- 5楼网友:没感情的陌生人
- 2021-04-26 22:16