求89C51单片机简单中断程序,用C语言编写,题目如图
答案:1 悬赏:10
解决时间 2021-01-20 17:18
- 提问者网友:那叫心脏的地方装的都是你
- 2021-01-19 17:07
求89C51单片机简单中断程序,用C语言编写,题目如图
最佳答案
- 二级知识专家网友:污到你湿
- 2021-01-19 18:25
#include
#include "intrins.h"
#include "absacc.h"
#define uchar unsigned char
uchar ledtab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40,0xff};//0-9
uchar num,cnt;
bit flag=0;
void ext1() interrupt 2
{
flag=~flag;
}
void t1isr() interrupt 3//显示
{
TH1=0xec;
TL1=0x78;
P0=0xff;
P2=0xfe;
P0=ledtab[num];
cnt++;
if(cnt>=200)
{
cnt=0;
if(flag==0)num++;
num%=10;
}
}
main()
{
TMOD=0x10;
TH1=0xec;
TL1=0x78;
TR1=1;
ET1=1;
EX1=1;
IT1=1;
EA=1;
while(1);
}
#include "intrins.h"
#include "absacc.h"
#define uchar unsigned char
uchar ledtab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x40,0xff};//0-9
uchar num,cnt;
bit flag=0;
void ext1() interrupt 2
{
flag=~flag;
}
void t1isr() interrupt 3//显示
{
TH1=0xec;
TL1=0x78;
P0=0xff;
P2=0xfe;
P0=ledtab[num];
cnt++;
if(cnt>=200)
{
cnt=0;
if(flag==0)num++;
num%=10;
}
}
main()
{
TMOD=0x10;
TH1=0xec;
TL1=0x78;
TR1=1;
ET1=1;
EX1=1;
IT1=1;
EA=1;
while(1);
}
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