(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
答案:2 悬赏:60
解决时间 2021-01-04 10:49
- 提问者网友:南佳人~
- 2021-01-04 05:17
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
最佳答案
- 二级知识专家网友:不服输的倔强
- 2021-01-04 06:48
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
全部回答
- 1楼网友:偏爱自由
- 2021-01-04 07:34
(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-1
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)-1
=(2^8-1)(2^8+1)(2^16+1)-1
=(2^16-1)(2^16+1)-1
=2^32-1-1
=2^31
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