python读取脚本所在目录文件名,放到aa.txt文件中,然后读取aa.txt文件的每一行,一行作为一个文件名,并打开,现在打开总是报错invalid argument:'bb.txt\n'
代码如下
import os
path = os.getcwd()
for filename in os.listdir(path):
f = open('aa.txt','a')
f = write(filename)
f = write("\n")
f.close
f = open('aa.txt')
line = f.readline()
while line:
inFile = line
if inFile:
filehandle = open(inFile)
line = f.readline()
f.close()
filehandle.close()
python读取脚本所在目录文件名,放到aa.txt文件中,然后读取aa.txt文件的每
答案:2 悬赏:0
解决时间 2021-02-19 13:52
- 提问者网友:追忆成伤
- 2021-02-18 21:46
最佳答案
- 二级知识专家网友:青春如此荒謬
- 2021-02-18 22:44
import os
path = os.getcwd()
f = open('aa.txt','a')
for filename in os.listdir(path):
fullname=os.path.join(path,filename)
if os.path.isfile(fullname):
f.write(fullname)
f.write("\n")
f.close()
f = open('aa.txt')
for line in f:
infile=line.rstrip('\n')
filehandle=open(infile)
filehandle.close()
f.close()
path = os.getcwd()
f = open('aa.txt','a')
for filename in os.listdir(path):
fullname=os.path.join(path,filename)
if os.path.isfile(fullname):
f.write(fullname)
f.write("\n")
f.close()
f = open('aa.txt')
for line in f:
infile=line.rstrip('\n')
filehandle=open(infile)
filehandle.close()
f.close()
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- 1楼网友:恕我颓废
- 2021-02-18 23:42
谁想要的话发邮箱。
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