计算:1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
答案:3 悬赏:30
解决时间 2021-01-08 15:58
- 提问者网友：夢醒日落
- 2021-01-07 17:05
计算:1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
最佳答案
- 二级知识专家网友：迟山
- 2021-01-07 18:19
1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
=(x-1)/(x-2)(x-3)(x-1)-2(x-2)/(x-1)(x-2)(x-3)+(x-3)/(x-1)(x-2)(x-3)
=【x-1-2x＋4＋x-3】/(x-1)(x-2)(x-3)
=【0】/(x-1)(x-2)(x-3)
=0
=(x-1)/(x-2)(x-3)(x-1)-2(x-2)/(x-1)(x-2)(x-3)+(x-3)/(x-1)(x-2)(x-3)
=【x-1-2x＋4＋x-3】/(x-1)(x-2)(x-3)
=【0】/(x-1)(x-2)(x-3)
=0
全部回答
- 1楼网友：神鬼未生
- 2021-01-07 20:08
=1/(x-3)-1/(x-2)-1/(x-3)+1/(x-1)+1/(x-2)-1/(x-1)=0
- 2楼网友：夜风逐马
- 2021-01-07 19:29
=[(x-1)-2(x-2)+(x-3)]/(x-1)(x-2)(x-3)
=0
=0
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