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c语言。修改。21点的牌类游戏[代码太大分两次发].part02

答案:1  悬赏:60  
解决时间 2021-04-07 01:43
else printf(" return cardDrawn;Queen&quot,&quot, int cards[52]) { int cardDrawn;%s\= total[DEALER]) && (total[PLAYER] <);),total[DEALER]); if(cardDrawn == 1) { printf("You wins; points[ACEHIGH] += 10; getchar(); cards[subDraw] = cards[*numCards - 1] (*numCards);%s\King" ans = getchar(); points[ACELOW] += 10,"%s%c" return;%s"; return toupper(ans); 25) {printf("); while (i < return; printf(" 21) && (total[PLAYER]) > 21) {printf(" printf(" } } return;n");n" break; } if((total[DEALER]) > case(13) ;: points[ACELOW] += cardDrawn;%d\n" } if((total[DEALER] >You have a total of %d\ subDrawn = (rand() % (*numCards)); points[ACEHIGH] += 10; points[ACEHIGH] += 10; 21) {printf(&quot, cards););Ace" } } char getAns(char mesg[]) { char ans; } void dispTitle(void) { int i = 0,BELL); } void dispCard(itn cardDrawn; break;; i++void dealerGetsCard(int * numCards;); default ; cardDrawn = cards[subDraw];: printf("Nobody wins," dispCard(newcard;%s&quot,"Jack"n" return;\ break;); else total[who] = points[ACEHIGH];%s\; } else { points[ACEHIGH] += cardDrawn;n&quot: printf("The house stands with a total of %d\ points[ACELOW] += 10; return,cardDrawn);;%s\.\ } if((total[PLAYER]) > printf(" } return;);n\ } void findWinner(int total[2]) { if(total[DEALER] == 21) {printf(", int playerPoints[2]) { int newCard;= total[PLAYER]) && (total[DEALER] <n"n"n"n" } void totalIt(int points[2];The house wins.\: printf(" srand((unsigned)time(NULL));n" newCard = dealCard(numCards;, " } int dealCard(int * numCards, int total[2]; points[ACEHIGH] += 11;n&quot, dealerPoints);), int points[2]) { switch (cardDrawn) { case(11) ;The dealer draw,mesg);The house wins; return,total[PLAYER]);n&quot: " if(who == PLAYER) printf(".\,&quot, subDraw;; case(12) ; points[ACELOW] += 10;; 21) {printf("n\, int who) { if((points[ACELOW] == points[ACEHIGH]) || (points[ACEHIGH] &gt.\ 21)) total[who] = points[ACELOW], int cards[52]
最佳答案
21
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