(2√2+3)²°¹²(2√2-3)²°¹³-4√(1/8)
答案:1 悬赏:0
解决时间 2021-01-07 14:32
- 提问者网友：爱了却不能说
- 2021-01-06 17:40
(2√2+3)²°¹²(2√2-3)²°¹³-4√(1/8)
最佳答案
- 二级知识专家网友：孤老序
- 2021-01-06 18:14
(2√2+3)²°¹²(2√2-3)²°¹³-4√(1/8)
=(2√2+3)²°¹²(2√2-3)²°¹²(2√2-3)-√(4²×1/8)
=[(2√2+3)(2√2-3)]²°¹²(2√2-3)-√(16×1/8)
=(8-9)²°¹²(2√2-3)-√2
=(-1)²°¹²(2√2-3)-√2
=2√2-3-√2
=√2-3
=(2√2+3)²°¹²(2√2-3)²°¹²(2√2-3)-√(4²×1/8)
=[(2√2+3)(2√2-3)]²°¹²(2√2-3)-√(16×1/8)
=(8-9)²°¹²(2√2-3)-√2
=(-1)²°¹²(2√2-3)-√2
=2√2-3-√2
=√2-3
我要举报
如以上问答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
大家都在看
推荐资讯