计算:(1)/(2-a)-((a+2)/(a²-2a)-(a-1)/(a²-4a+4))÷(a-4)/(2a)
答案:2 悬赏:50
解决时间 2021-02-17 21:26
- 提问者网友:孤笛钟情你
- 2021-02-17 13:56
计算:(1)/(2-a)-((a+2)/(a²-2a)-(a-1)/(a²-4a+4))÷(a-4)/(2a)
最佳答案
- 二级知识专家网友:甜野猫
- 2021-02-17 15:21
原式=-1/(a-2)-[(a+2)/a(a-2)-(a-1)/(a-2)²]×2a/(a-4)
=-1/(a-2)-[(a+2)(a-2)-a(a-1)]/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a²-4-a²+a)/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a-4)/a(a-2)²×2a/(a-4)
=-1/(a-2)-2/(a-2)²
=-(a-2+2)/(a-2)²
=-a/(a-2)²
=-1/(a-2)-[(a+2)(a-2)-a(a-1)]/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a²-4-a²+a)/a(a-2)²×2a/(a-4)
=-1/(a-2)-(a-4)/a(a-2)²×2a/(a-4)
=-1/(a-2)-2/(a-2)²
=-(a-2+2)/(a-2)²
=-a/(a-2)²
全部回答
- 1楼网友:我的任性你不懂
- 2021-02-17 16:39
原式=[(a-2)/a(a+2)-(a-1)/(a+2)²]×[(a+2)/(a-4)]
={[(a-2)(a+2)-a(a-1)]/a(a+2)²}×[(a+2)/(a-4)]
=[(a²-4-a²+a)/a(a+2)²}×[(a+2)/(a-4)]
=[(a-4)/a(a+2)²}×[(a+2)/(a-4)]
=1/(a²+2a)
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