java中怎么把20140124103709转换成yyyy-MM-dd hh:mm:ss形式的日期啊？

java中怎么把20140124103709转换成yyyy-MM-dd hh:mm:ss形式的日期啊？

public String changeTime(String time,)throws Exception{
if(StringUtil.isNull(time)){
throw new Exception("The time must not be null or ''");
}
SimpleDateFormat oldFormat = new SimpleDateFormat("yyyyMMddHHmmss");
SimpleDateFormat newFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = oldFormat.parse(time);
return newFormat.format(date);
}

Date date = sdf1.parse(); //yyyyMMddHHmmss sdf2.format(date)////yyyy-MM-dd HH:mm:ss

String s = "20140124103709"; SimpleDateFormat sdf1 = new SimpleDateFormat("yyyyMMddhhmmss"); Date date = (Date) sdf1.parse(s); SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); System.out.print(sdf2.format(date));

给你一段代码，使用它就可以实现 SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); String dateString = "20140124103709"; try { Date date = df.parse(dateString); System.out.println(df.format(date)); } catch (Exception ex) { System.out.println(ex.getMessage()); } }

String sDateStr="20140124103709";         SimpleDateFormat sdf=new SimpleDateFormat("yyyyMMddhhmmss");         try {             System.out.println(sdf.parse(sDateStr));         } catch (ParseException e) {             //做转化失败的操作         }     }应该这样就能满足你的要求了,不过要注意判断长度是否都是14位,以防转换出错

public static string datetostring(date time){ simpledateformat formatter; formatter = new simpledateformat ("yyyy-mm-dd hh:mm:ss"); string ctime = formatter.format(time); return ctime; }