(123456789/123456788-123456788/123456789)÷(1/123456788+1/123456789)
答案:6 悬赏:80
解决时间 2021-02-22 04:53
- 提问者网友:疯子也有疯子的情调
- 2021-02-21 17:31
(123456789/123456788-123456788/123456789)÷(1/123456788+1/123456789)
最佳答案
- 二级知识专家网友:拜訪者
- 2021-02-21 18:41
转换一下,a=123456788,b=123456789
原式=(b/a-a/b)/(1/a+1/b)
=[(b^2-a^2)/ab]/[(b+a)/ab]
=(b^2-a^2)/(b+a)
=(b+a)(b-a)/(b+a)
=b-a
=123456789-123456788
=1
原式=(b/a-a/b)/(1/a+1/b)
=[(b^2-a^2)/ab]/[(b+a)/ab]
=(b^2-a^2)/(b+a)
=(b+a)(b-a)/(b+a)
=b-a
=123456789-123456788
=1
全部回答
- 1楼网友:一秋
- 2021-02-22 00:06
(123456789/123456788-123456788/123456789)÷(1/123456788+1/123456789)
=[(123456789^2-123456788^2)/(123456788*123456789)]/[(123456788+123456789)/(123456788*123456789)]
=(123456789^2-123456788^2)/(123456788+123456789)
=123456789-123456788=1
=[(123456789^2-123456788^2)/(123456788*123456789)]/[(123456788+123456789)/(123456788*123456789)]
=(123456789^2-123456788^2)/(123456788+123456789)
=123456789-123456788=1
- 2楼网友:举杯邀酒敬孤独
- 2021-02-21 23:08
(123456789/123456788-123456788/123456789)÷(1/123456788+1/123456789)
=(1+1/123456788-1+1/123456789)÷(1/123456788+1/123456789)
=(1/123456788+1/123456789)÷(1/123456788+1/123456789)
=1
=(1+1/123456788-1+1/123456789)÷(1/123456788+1/123456789)
=(1/123456788+1/123456789)÷(1/123456788+1/123456789)
=1
- 3楼网友:杯酒困英雄
- 2021-02-21 22:27
原式=(1 1/123456788-1 1/123456789)/(1/123456788 1/123456789)=1
简便算法的核心就是把分子分离一下化简 如123456789/123456788=(123456788 1)/123456788
简便算法的核心就是把分子分离一下化简 如123456789/123456788=(123456788 1)/123456788
- 4楼网友:白昼之月
- 2021-02-21 20:52
设 123456789 = a, 123456788 = b;
则原式变作
( a/b - b/a ) / ( 1/b + 1/a ) = ( a^2 - b^2) / ab * ab / ( a + b) = a - b = 123456789 - 123456788 = 1;
答案是1,
正确的话 给个最佳答案,码字不容易呢
则原式变作
( a/b - b/a ) / ( 1/b + 1/a ) = ( a^2 - b^2) / ab * ab / ( a + b) = a - b = 123456789 - 123456788 = 1;
答案是1,
正确的话 给个最佳答案,码字不容易呢
- 5楼网友:拾荒鲤
- 2021-02-21 19:21
X=123456789,123456788=X-1
原式=[X/(X-1)-(X-1)/X]/[1/(X-1)+1/X]
=[(X²-(X-1)²)/(X(X-1))]/[(X+(X-1))/(X(X-1))]
=[X²-(X²-2X+1)]/[2X-1]
=(2X-1)/(2X-1)
= 1
答案与X无关
原式=[X/(X-1)-(X-1)/X]/[1/(X-1)+1/X]
=[(X²-(X-1)²)/(X(X-1))]/[(X+(X-1))/(X(X-1))]
=[X²-(X²-2X+1)]/[2X-1]
=(2X-1)/(2X-1)
= 1
答案与X无关
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