用c++完成
课程设计:学生综合测评成绩之德育成绩管理系统
(含早操、课堂、晚点名考勤,寝室纪律卫生,参加各类比赛评优评奖情况)
学生相关信息:学号,姓名,性别,成绩,家庭地址,宿舍号,家庭困难档次
事项信息:事件名、时间、地点、当事人、事项管理单位、检查成绩、对应分数等
具体分值等请参照(宜宾学院现行学生手册。)
要求:1)系统以菜单方式工作
2)能实现数据的输入,修改,查询,删除。
3)根据输入项进行加减操行分,分数汇总,最后计算
谢谢你了大侠,我看你跟别个都做的那么完美。实在是麻烦你了帮帮忙吧!
学生综合测评成绩之德育成绩管理系统
答案:2 悬赏:70
解决时间 2021-04-28 13:54
- 提问者网友:沉默的哀伤
- 2021-04-27 20:46
最佳答案
- 二级知识专家网友:不服输就别哭
- 2021-04-27 21:38
如果系统不支持中文,姓名要按英文输入,例如:
1 zhang_san 100 100 100 100
2 li_si 50 50 50 50
3 wang_wu 60 70 80 90
4 zhao_liu 70 70 80 90
----------------------------------
#include
#include
typedef struct stu{
int id;
char name[40];
int mark[4];
float total;
} STU;
int id;
int m1,m2,m3,m4;
char str[40];
void main()
{
int i,j,N=0;
FILE *fin, *fout;
STU tmp;
STU *s;
fin = fopen("score.txt","r");
while (1){
if ( fscanf(fin,"%*d %*s %*d %*d %*d %*d") ==EOF) break;
N++;
}
fclose(fin);
s = (STU *) malloc(N * sizeof(STU));
if (!s) {
printf("no enough memory for STU\n"); exit(0);
}
fin = fopen("score.txt","r");
for (i=0;i
fscanf(fin,"%d %s %d %d %d %d",&id,&str[0],&m1,&m2,&m3,&m4);
s[i].id = id;
strcpy(&s[i].name[0],str);
s[i].mark[0]= m1;
s[i].mark[1]= m2;
s[i].mark[2]= m3;
s[i].mark[3] = m4;
s[i].total = 0.2*m1 + 0.6*m2 + 0.5 * m3 + 0.15*m4;
}
fclose(fin);
for (i=0;i
for (j=i+1;j
if (s[j].total > s[i].total){
tmp = s[j]; s[j]=s[i];s[i]=tmp;
};
};
};
fout = fopen("score_Q.txt","w");
for(i=0;i
fprintf(fout,"%d %s %d %d %d %d\n",s[i].id,s[i].name,s[i].mark[0],s[i].mark[1],s[i].mark[2],s[i].mark[3]);
}
fclose(fout);
exit(0);
}
你的串号我已经记下,采纳后我会帮你制作
你的串号我已经记下,采纳后我会帮你制作
1 zhang_san 100 100 100 100
2 li_si 50 50 50 50
3 wang_wu 60 70 80 90
4 zhao_liu 70 70 80 90
----------------------------------
#include
#include
typedef struct stu{
int id;
char name[40];
int mark[4];
float total;
} STU;
int id;
int m1,m2,m3,m4;
char str[40];
void main()
{
int i,j,N=0;
FILE *fin, *fout;
STU tmp;
STU *s;
fin = fopen("score.txt","r");
while (1){
if ( fscanf(fin,"%*d %*s %*d %*d %*d %*d") ==EOF) break;
N++;
}
fclose(fin);
s = (STU *) malloc(N * sizeof(STU));
if (!s) {
printf("no enough memory for STU\n"); exit(0);
}
fin = fopen("score.txt","r");
for (i=0;i
s[i].id = id;
strcpy(&s[i].name[0],str);
s[i].mark[0]= m1;
s[i].mark[1]= m2;
s[i].mark[2]= m3;
s[i].mark[3] = m4;
s[i].total = 0.2*m1 + 0.6*m2 + 0.5 * m3 + 0.15*m4;
}
fclose(fin);
for (i=0;i
tmp = s[j]; s[j]=s[i];s[i]=tmp;
};
};
};
fout = fopen("score_Q.txt","w");
for(i=0;i
}
fclose(fout);
exit(0);
}
你的串号我已经记下,采纳后我会帮你制作
你的串号我已经记下,采纳后我会帮你制作
全部回答
- 1楼网友:时光挺欠揍
- 2021-04-27 21:44
如果系统不支持中文,姓名要按英文输入,例如:
1 zhang_san 100 100 100 100
2 li_si 50 50 50 50
3 wang_wu 60 70 80 90
4 zhao_liu 70 70 80 90
----------------------------------
#include <stdio.h>
#include <stdlib.h>
typedef struct stu{
int id;
char name[40];
int mark[4];
float total;
} stu;
int id;
int m1,m2,m3,m4;
char str[40];
void main()
{
int i,j,n=0;
file *fin, *fout;
stu tmp;
stu *s;
fin = fopen("score.txt","r");
while (1){
if ( fscanf(fin,"%*d %*s %*d %*d %*d %*d") ==eof) break;
n++;
}
fclose(fin);
s = (stu *) malloc(n * sizeof(stu));
if (!s) {
printf("no enough memory for stu\n"); exit(0);
}
fin = fopen("score.txt","r");
for (i=0;i<n;i++){
fscanf(fin,"%d %s %d %d %d %d",&id,&str[0],&m1,&m2,&m3,&m4);
s[i].id = id;
strcpy(&s[i].name[0],str);
s[i].mark[0]= m1;
s[i].mark[1]= m2;
s[i].mark[2]= m3;
s[i].mark[3] = m4;
s[i].total = 0.2*m1 + 0.6*m2 + 0.5 * m3 + 0.15*m4;
}
fclose(fin);
for (i=0;i<n-1;i++){
for (j=i+1;j<n;j++){
if (s[j].total > s[i].total){
tmp = s[j]; s[j]=s[i];s[i]=tmp;
};
};
};
fout = fopen("score_q.txt","w");
for(i=0;i<n;i++){
fprintf(fout,"%d %s %d %d %d %d\n",s[i].id,s[i].name,s[i].mark[0],s[i].mark[1],s[i].mark[2],s[i].mark[3]);
}
fclose(fout);
exit(0);
}
你的串号我已经记下,采纳后我会帮你制作
你的串号我已经记下,采纳后我会帮你制作
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