for($y=2012;$y<=2015;$y++)
{
echo("
for($m=01;$m<=12;$m++)
{
echo("
}
echo("
}
?>
生成表格
while($row=mysql_fetch_array($rs_topsharing))
{
$issue=$row["issue"];
$issue_y=substr($issue,0,4);
$issue_m=substr($issue,5,2);
if($y==$issue_y&&$m==$issue_m)
{
echo("
}
else
{
echo("
}
}
$issue=2012-04-05
当$m等于4时可以输出
echo("
怎么办 急急急 谢谢大哥大姐们帮忙