cb编程输出a到z的代码和字符的对应表
答案:1 悬赏:50
解决时间 2021-02-17 11:50
- 提问者网友:泪痣哥哥
- 2021-02-17 07:33
cb编程输出a到z的代码和字符的对应表
最佳答案
- 二级知识专家网友:天凉才是好个秋
- 2021-02-17 08:51
func mergeSort(r []int) []int {
length := len(r)
if length <= 1 {
return r
}
num := length / 2
left := mergeSort(r[:num])
right := mergeSort(r[num:])
return merge(left, right)
}
func merge(left, right []int) (result []int) {
l, r := 0, 0
for l < len(left) && r < len(right) {
if left[l] < right[r] {
result = append(result, left[l])
l++
} else {
result = append(result, right[r])
r++
}
}
result = append(result, left[l:]...)
result = append(result, right[r:]...)
return
}
length := len(r)
if length <= 1 {
return r
}
num := length / 2
left := mergeSort(r[:num])
right := mergeSort(r[num:])
return merge(left, right)
}
func merge(left, right []int) (result []int) {
l, r := 0, 0
for l < len(left) && r < len(right) {
if left[l] < right[r] {
result = append(result, left[l])
l++
} else {
result = append(result, right[r])
r++
}
}
result = append(result, left[l:]...)
result = append(result, right[r:]...)
return
}
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