2.496/(1.15+1.1x)*2/3=x
matlab解高次方程
答案:2 悬赏:40
解决时间 2021-03-01 06:27
- 提问者网友:心裂忍耐
- 2021-02-28 18:26
最佳答案
- 二级知识专家网友:星星坠落
- 2021-02-28 18:48
x = solve('2.496/(1.15+1.1*x)^(2/3) - x')
x =
1.3195550641620025031518455873621
0.12754856360044580617036333878508 - 1.5136031252504207486961030519838*i
0.12754856360044580617036333878508 + 1.5136031252504207486961030519838*i
- 1.8327806411359925122917406779207 - 0.92843775822495439933866302968229*i
- 1.8327806411359925122917406779207 + 0.92843775822495439933866302968229*i
x =
1.3195550641620025031518455873621
0.12754856360044580617036333878508 - 1.5136031252504207486961030519838*i
0.12754856360044580617036333878508 + 1.5136031252504207486961030519838*i
- 1.8327806411359925122917406779207 - 0.92843775822495439933866302968229*i
- 1.8327806411359925122917406779207 + 0.92843775822495439933866302968229*i
全部回答
- 1楼网友:抱不住太阳的深海
- 2021-02-28 19:18
fun=inline('5*x^23-6*x^7+8*x^6-5*x^2 ','x')
fun =
inline function:
fun(x) = 5*x^23-6*x^7+8*x^6-5*x^2
fzero(fun,[-2,2])
ans =
0.9768
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