用C语言函数判断这一天是这一年的第几天？例如输入1998,1,1或者1998/1/1或者1998-1-1都可以

帮下忙谢谢谢谢大家啦。。。。
更主要是那个输入。。。就是1998/1/1或者1998-1-1或者别的格式输入都可以

#include <stdio.h>
#include <stdlib.h>
static int daytable[2][13] = {
{0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
{0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
};
void get_day ( int year, int *dayofyear, int month, int day )
{
int i, leap;
leap = (( year % 4 == 0 ) && ( year % 100 != 0 ) || ( year % 400 == 0 ));
*dayofyear = 0;
for (i=1;i< month;i++) {
*dayofyear = *dayofyear + daytable[leap][i];
}
*dayofyear = *dayofyear + day;
}

void main()
{
char s[12];
int y,m,d;
int jd;
int i,L;
printf("input 1998-1-1 year-month-day\n");
fscanf(stdin,"%s",s);
L = strlen(s);
for (i=0;i<L;i++) if (s[i] < '0' || s[i] > '9') s[i]=' ';
sscanf(s,"%d %d %d",&y,&m,&d);
printf("%d %d %d\n",y,m,d);
(void) get_day ( y, &jd, m, d );
printf("the J day=%d\n",jd);
}
-----------
1998/1/1 1998-1-1 1998,2,2 年符号月符号日符号都可以

#include<stdio.h> main() {int Y,M,D,a[13]={366,31,29,31,30,31,30,31,31,30,31,30,31}, b[13]={365,31,28,31,30,31,30,31,31,30,31,30,31},E,i; K:scanf("%d %d %d",&Y,&M,&D); if((Y%4==0&&Y%100!=0)||(Y%4==0&&Y%400==0)) {E=0; for(i=1;i<M;i++) E=E+a[i]; printf("It is the year's first %d day.\n",E+D);} else {E=0; for(i=1;i<M;i++) E=E+b[i]; printf("It is the year's first %d day.\n",E+D);} goto K; getch();}

可以输入1998/1/1或者1998-1-1 1998.1.1 #include #include void main() { int month1[11]={31,28,31,30,31,30,31,31,30,31,30};//每月天数 int month2[11]={31,29,31,30,31,30,31,31,30,31,30};//闰年每月天数 int i,year,month,day,count=0; printf("年,月,日:"); scanf("%d%*c%d%*c%d",&year,&month,&day); if( (year%4==0&&year%100

可以输入1998/1/1或者1998-1-1 1998.1.1 #include<stdio.h> #include<windows.h> void main() { int month1[11]={31,28,31,30,31,30,31,31,30,31,30};//每月天数 int month2[11]={31,29,31,30,31,30,31,31,30,31,30};//闰年每月天数 int i,year,month,day,count=0; printf("年,月,日:"); scanf("%d%*c%d%*c%d",&year,&month,&day); if( (year%4==0&&year%100!=0)||(year%400==0) )//判断是否为闰年 for(i=0;i<month-1;i++) count+=month2[i]; else for(i=0;i<month-1;i++) count+=month1[i]; count+=day; printf("%d.%d.%d是这%d年第%d天\n",year,month,day,year,count); system("pause"); }