设有n个人围坐一圈并按顺时针方向从1到n编号,从第s个人开始进行1到m的报数,请问下面的程序哪地方错了？

设有n个人围坐一圈并按顺时针方向从1到n编号，从第s个人开始进行1到m的报数，报数到第m个人，此人出圈，再从他的下一个人重新开始1到m的报数，如此进行下去直到所有的人都出圈为止。现要求按出圈次序，每10人一组，给出这n个人的顺序表。编制函数Josegh()实现此功能


#include<stdio.h>
#include<stdlib.h>
int n,s,m,out,a[100]; //n为所有人数，out为出局的人
void josegh( );
void main()
{
int i;
for (i = 1; i < 100; i++) //定义数组a[100],按顺序赋值1 -3
a[i] = i;
printf ("n = "); scanf ("%d", &n);
printf ("s = "); scanf ("%d", &s);
printf ("m = "); scanf ("%d", &m);
out = s + m -1;
if (out > n)
out = out - n;
printf ("out = %d",a[out]);
n --;
while (out <= n)
a[out] = a[++out];

while (n != 0)
{
printf("\nm = ");
scanf("%d", &m);
josegh ( );
}
system("pause");
}
void josegh ( ) //每当出局一个人，n减1，数组重新排列
{
if (m > n)
m = m - n;
else if (m <= n)
printf ("o = %d",a[m]);
n--;
while (m <= n)
a[m] = a[++m];
}

最后一步，o应该等于2，怎么会是1呢？

#include<stdio.h>
#include<stdlib.h>
int n,s,m,out,a[100];
void josegh( );
void main()
{
int i;
printf ("n = "); scanf ("%d", &n);

printf ("s = "); scanf ("%d", &s);
printf ("m = "); scanf ("%d", &m);
for (i = 1; i <=n; i++)
a[i] = i;
while (n != 0)

josegh ( );
system("pause");
}
void josegh ( )
{
out = s + m - 1;

while (out > n)
out-= n;
printf ("o = %d\n",a[out]);
n--;
s=out;
while (out <= n)
a[out++] = a[out+1];
}