根据输入1~12之间的数字，判断是春夏秋冬那个季节，要求使用方法定义四个季节。用switch

答案:3 悬赏:40

解决时间 2021-02-12 16:49

提问者网友：熱戀丶瘋
2021-02-11 18:18

最佳答案

二级知识专家网友：虚伪的现实
2021-02-11 19:21

public String whichSeason(int month) {

String season;

switch(month) {

case 1:
case 2;

case 3:
season = "该季节为春季";

break;
case 4:
case 5:

case 6:
season = "该季节为夏季";

break;

case 7:

case 8:

case 9:
season = "该季节为秋季";

break;

case 10:

case 11:

case 12:

season = "该季节为冬季";

break;

default:

season = "wrong month!";

}
return season;

}

全部回答

1楼网友：心与口不同
2021-02-11 21:19

苹果系统键盘控制面板不好使怎么办苹果系统键盘控制面板不好使怎么办

2楼网友：一只傻青衣
2021-02-11 20:20

public string judgeSeason(int number) { String season = ""; swithch(number) { case 1: season="春"; break; case 2: season="春"; break; case 3: season="春"; break; case 4: season="夏"; break; case 5: season="夏"; break; case 6: season="夏"; break; case 7: season="秋"; break; case 8: season="秋"; break; case 9: season="秋"; break; case 10: season="冬"; break; case 11: season="冬"; break; case 12: season="冬"; break; } return season; } main里边 system.out.println("该季节为"+season+"季")；

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根据输入1~12之间的数字，判断是春夏秋冬那个季节，要求使用方法定义四个季节。 用switch

根据输入1~12之间的数字，判断是春夏秋冬那个季节，要求使用方法定义四个季节。用switch