有如下表格
要求如下,不增加新的列,不先计算现在和生产日期的时间差,直接在下表中体现,能有做到,谢谢!
刚才忘记说了,这个计算要是动态的,也就是说我2015年打开和2016年打开,里面的数据是会实时修正的,谢谢!
excel表格统计使用年限
答案:2 悬赏:0
解决时间 2021-02-21 15:34
- 提问者网友:独菊痴梦
- 2021-02-20 17:12
最佳答案
- 二级知识专家网友:末路丶一枝花
- 2021-02-20 17:41
1年以下:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=0))
1-2年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=1))
2-3年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=2))
3-4年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=3))
4-5年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=4))
5年及以上:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")>=5))
Datedif(开始日期,结束日期,"y")得到的结果是周年,对年对月对日,因此,结果为=1就是1周年以上不到2周年,其他同理。
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=0))
1-2年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=1))
2-3年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=2))
3-4年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=3))
4-5年:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")=4))
5年及以上:
=SUMPRODUCT(N(DATEDIF($C$2:$C$15,TODAY(),"y")>=5))
Datedif(开始日期,结束日期,"y")得到的结果是周年,对年对月对日,因此,结果为=1就是1周年以上不到2周年,其他同理。
全部回答
- 1楼网友:高冷不撩人
- 2021-02-20 18:44
看了你的求助,一是想不出好的方法。但你提示“急”,先介绍一个笨方法:
c4单元格公式:
=a4&if(a3=a4,"",a3)&if(a2=a4,"",if(a2=a3,"",a2))&if(a1=a4,"",if(a1=a3,"",if(a1=a2,"",a1)))
c5单元格公式:
=left(a5&if(a4=a5,"",a4)&if(a3=a5,"",if(a3=a4,"",a3))&if(a2=a5,"",if(a2=a4,"",if(a2=a3,"",a2)))&if(a1=a5,"",if(a1=a4,"",if(a1=a3,"",if(a1=a2,"",a1)))),4)
c6单元格公式:
=left(a6&if(a5=a6,"",a5)&if(a4=a6,"",if(a4=a5,"",a4))&if(a3=a6,"",if(a3=a5,"",if(a3=a4,"",a3)))&if(a2=a6,"",if(a2=a5,"",if(a2=a4,"",if(a2=a3,"",a2))))&if(a1=a6,"",if(a1=a5,"",if(a1=a4,"",if(a1=a3,"",if(a1=a1,"",a1))))),4)
将c6单元格公式拖下去,效果如图:
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