(1+1/2)+(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
答案:2 悬赏:50
解决时间 2021-02-02 00:58
- 提问者网友：美人如花
- 2021-02-01 14:14
(1+1/2)+(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
最佳答案
- 二级知识专家网友：你好陌生人
- 2021-02-01 14:30
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2²)(1+1/2^2)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^8)(1-1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^16)÷(1-1/2)+1/2^15
=1-1/2^15+1/2^15
=1
=(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2²)(1+1/2^2)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^4)(1+1/2^4)(1+1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^8)(1-1/2^8)÷(1-1/2)+1/2^15
=(1-1/2^16)÷(1-1/2)+1/2^15
=1-1/2^15+1/2^15
=1
全部回答
- 1楼网友：废途浑身病态
- 2021-02-01 14:51
1+1/2）(1+1/2²)（1+1/2的四次方）（1+1/2的八次方）
=（1-1/2)1+1/2）(1+1/2²)（1+1/2的四次方）（1+1/2的八次方）/(1-1/2)
=(1-1/2²)(1+1/2的四次方）（1+1/2的八次方）+1/2的15次/(1/2)
=2(1-1/2的四次方))(1+1/2的四次方）（1+1/2的八次方）
=2(1-1/2的十六次方
1+1/2）(1+1/2²)（1+1/2的四次方）（1+1/2的八次方）+1/2的15次方
=2-1/2的15次方）+1/2的15次方
=2
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