Java单词恢复~求高手解答下。输入字符串的个数~然后输入一个乱了顺序的字符串，~

样例输入
4
School boy student tree
ybo

样例输出

boy

替你写了段代码，测试通过。

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int lineCount = 0;
int length = 0;
String[] words = null;
Scanner cin = new Scanner(System.in);
System.out.print("");
while (cin.hasNext()){
lineCount++;
String str = cin.nextLine();
String[] substr = str.split(" ");
switch (lineCount) {
case 1 :
length = Integer.parseInt(substr[0]);
words = new String[length];
break;
case 2 :
for (int i = 0; i < length; i++) {
words[i] = substr[i];
}
break;
case 3 :
str = substr[0];
for (int i = 0; i < length; i++) {
String word = words[i];
if (word.length() == str.length()) {
boolean sameFlag = true;
int j = 0;
while (j < str.length() && sameFlag) {
String ch = str.substring(j, j + 1);
sameFlag = word.contains(ch);
j++;
}
if (sameFlag) {
System.out.println(word);
}
}
}
break;
}
}
}
}

理论上讲，很简单，但是实际写出来还是有点小恶心，代码如下，测试无误： public class teststring { public static void main(string[] args) { docount("abc a bc abc bc abc", " "); } public static void docount(string sourcestring, string delimiter) {//sourcestring为需要统计的字符串，delimiter为字符串拆分符 list result = new arraylist();//用来进行统计操作的集合 list last = new arraylist();//存储统计结果的集合 string target[] = sourcestring.split(delimiter);//目标字符串数组 for (int i = 0; i < target.length; i++) { result.add(target[i]); } do { int num = 1; string info = result.get(0); result.remove(0); for (int k = 0; k < result.size(); k++) { if (info.equals(result.get(k))) { num++; result.remove(k); } } last.add(num + "-" + info); } while (result.size() > 0); collections.sort(last); collections.reverse(last); iterator it = last.iterator(); while (it.hasnext()) { string outcount[] = it.next().split("-"); system.out.println(outcount[1] + "的个数:" + outcount[0]); } } }