计算:3(2²+1)(2^4+1)(2^8+1)(2^16+1)
答案:4 悬赏:60
解决时间 2021-02-04 23:12
- 提问者网友:夜微涼
- 2021-02-04 03:44
计算:3(2²+1)(2^4+1)(2^8+1)(2^16+1)
最佳答案
- 二级知识专家网友:冷态度
- 2021-02-04 03:52
3(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2^2-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
=(2^2-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
全部回答
- 1楼网友:厌今念往
- 2021-02-04 08:03
3*(2^2+1)(2^4+1)(2^8+1)(2^16+1)+1 =(2^2-1) (2^2+1)(2^4+1)(2^8+1)(2^16+1)+1 =(2^4-1)(2^4+1)(2^8+1)(2^16+1)+1 =…… =2^32-1+1 =2^32
- 2楼网友:邪性洒脱
- 2021-02-04 06:25
(2ˆ2-1)(2ˆ2+1)(2ˆ4+1)(2ˆ8+1)(2ˆ16+1)
=(2ˆ4-1)(2ˆ4+1)(2ˆ8+1)(2ˆ16+1)
=(2ˆ8-1)(2ˆ8+1)(2ˆ16+1)
(2ˆ16-1)(2ˆ16+1)
=2ˆ32-1
可追问啊
- 3楼网友:猎杀温柔
- 2021-02-04 04:53
3(2^2+1)(2^4+1)(2^8+1)(2^16+1
=3(2²-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/(2²-1)
=3(2^4-1)(2^4+1)(2^8+1)(2^16+1)/(2²-1)
=3(2^8-1)(2^8+1)(2^16+1)/(2²-1)
=3(2^16-1)(2^16+1)/(2²-1)
=3(2^64-1)/3
=2^64-1
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