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请问大师135战法选股公式怎么放在软件里选股啊!!!急 ,这个公式能用吗

答案:2  悬赏:0  
解决时间 2021-03-24 20:07
{红杏出墙选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
AR1:=EMA55>EMA34 AND EMA34>EMA13;
AR2:=BARSLAST((C-EMA13)/EMA13*100<-6);
AR3:=EMA13>=REF(EMA13,2);
AR4:=COUNT(CROSS(C,EMA13),AR2)=1;
AR5:=AR1 AND AR2 AND AR3 AND AR4;
红杏出墙:AR5 AND FILTER(AR5,10);
------------------------
{蚂蚁上树选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
BR1:=COUNT(BETWEEN((C-REF(C,1))/REF(C,1)*100,0,5) ,5)=5;
BR2:=ABS((EMA13-EMA34)+(EMA34-EMA55))/C<0.2;
BR3:=C>EMA55 AND (REF(C,1)(C,4)蚂蚁上树:BR1 AND BR2 AND BR3;
---------------------------
{红衣侠女选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
EMA120:=EMA(C,120);
CR1:=(C-REF(C,1))/REF(C,1)*100>0.5;
CR2:=V>MA(V,5)*0.6;
CR3:=COUNT(CROSS(EMA13,EMA55),3)=1;
CR4:=ABS(EMA34-EMA55)/EMA55<0.03;
CR5:=EMA55<=EMA120 AND EMA55>=REF(EMA55,1);
红衣侠女:FILTER(CR1 AND CR2 AND CR3 AND CR4 AND CR5,2);
--------------------------
{黑客点击选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
DR1:=EMA13>EMA34 AND EMA34DR2:=BARSLAST(CROSS(C,EMA55) );
DR3:=H=HHV(H,DR2);
DR4:=BARSLAST(DR3);
DR5:=COUNT(O>C AND CEMA55 AND BETWEEN((C-EMA55)/EMA55,0,0.02),DR4)=1;
DR6:=C>REF(C,1) ;
DR7:=DR1 AND DR5 AND DR6 ;
黑客点击:DR7 AND FILTER(DR7,10);
--------------------------
{均线互换选股}
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
均线互换:BARSLAST(REF(CROSS(EMA55,EMA34),1)) AND CROSS(EMA34,EMA55);
--------------------------
{梅开二度选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
梅开二度:BARSLAST(REF(CROSS(EMA34,EMA13),1)) AND CROSS(EMA13,EMA34);
---------------------------------------
{三线推进选股}
EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
HR2:=EMA13>=REF(EMA13,3) AND EMA34>=REF(EMA34,1) AND EMA55>=REF(EMA55,1) AND CROSS(C,EMA13) AND
CROSS(C,EMA34) AND CROSS(C,EMA55);
三线推进:(HR2 AND FILTER(HR2,10));

我的软件是神枪手
最佳答案
修改了一下重复定义的。你也可以用你原来的源码,一个一个的新建这7个公式。

EMA13:=EMA(C,13);
EMA34:=EMA(C,34);
EMA55:=EMA(C,55);
EMA120:=EMA(C,120);
{红杏出墙选股}
AR1:=EMA55>EMA34 AND EMA34>EMA13;
AR2:=BARSLAST((C-EMA13)/EMA13*100<-6);
AR3:=EMA13>=REF(EMA13,2);
AR4:=COUNT(CROSS(C,EMA13),AR2)=1;
AR5:=AR1 AND AR2 AND AR3 AND AR4;
红杏出墙:=AR5 AND FILTER(AR5,10);
{蚂蚁上树选股}
BR1:=COUNT(BETWEEN((C-REF(C,1))/REF(C,1)*100,0,5) ,5)=5;
BR2:=ABS((EMA13-EMA34)+(EMA34-EMA55))/C<0.2;
BR3:=C>EMA55 AND (REF(C,1) (C,4) 蚂蚁上树:=BR1 AND BR2 AND BR3;
{红衣侠女选股}
CR1:=(C-REF(C,1))/REF(C,1)*100>0.5;
CR2:=V>MA(V,5)*0.6;
CR3:=COUNT(CROSS(EMA13,EMA55),3)=1;
CR4:=ABS(EMA34-EMA55)/EMA55<0.03;
CR5:=EMA55<=EMA120 AND EMA55>=REF(EMA55,1);
红衣侠女:=FILTER(CR1 AND CR2 AND CR3 AND CR4 AND CR5,2);
{黑客点击选股}
DR1:=EMA13>EMA34 AND EMA34 DR2:=BARSLAST(CROSS(C,EMA55) );
DR3:=H=HHV(H,DR2);
DR4:=BARSLAST(DR3);
DR5:=COUNT(O>C AND CEMA55 AND BETWEEN((C-EMA55)/EMA55,0,0.02),DR4)=1;
DR6:=C>REF(C,1) ;
DR7:=DR1 AND DR5 AND DR6 ;
黑客点击:=DR7 AND FILTER(DR7,10);
{均线互换选股}
均线互换:=BARSLAST(REF(CROSS(EMA55,EMA34),1)) AND CROSS(EMA34,EMA55);
{梅开二度选股}
梅开二度:=BARSLAST(REF(CROSS(EMA34,EMA13),1)) AND CROSS(EMA13,EMA34);
{三线推进选股}
HR2:=EMA13>=REF(EMA13,3) AND EMA34>=REF(EMA34,1) AND EMA55>=REF(EMA55,1) AND CROSS(C,EMA13) AND
CROSS(C,EMA34) AND CROSS(C,EMA55);
三线推进:=(HR2 AND FILTER(HR2,10));
XG:红杏出墙 OR 蚂蚁上树 OR 红衣侠女 OR 黑客点击 OR 均线互换 OR 梅开二度 OR 三线推进;
全部回答
volume:=vol; ma5v:=ma(v,5); ma35v:=ma(v,35); ma135v:=ma(v,135); rsv:=(close-llv(low,9))/(hhv(high,9)-llv(low,9))*100; k:=sma(rsv,3,1); d:=sma(k,3,1); j:=3*k-2*d; ww:=vol/ref(vol,1)>2; gg:=c>o; qq:=co and v>ma135v and cross(ma5v,ma135v); a1c:=count(a1,10); 介入1:=hc60天数>30 and not(除权) and abs(c-o)/o<0.03 and hc60跌幅>0.28 and hc7跌幅>0.065 and a1c=1 and v35 and not(除权) and abs(c-o)/o<0.03 and hc60跌幅>0.20 and (hc7跌幅>0.10 or (hc7跌幅>0.025 and c>ma(c,20))) and a1c=1 and v>ma35v and vo and v>ma135v and cross(ma5v,ma35v) and hc60跌幅>0.20; a2c:=count(a2,10); 介入2:=hc60天数>35 and not(除权) and abs(c-o)/o<0.03 and (o+c)/20.05 and ((c-ref(llv(c,7),1))/ref(llv(c,7),1)<0.01 or c>ma(c,20)) and a2c=1 and v35 and not(除权) and hc60跌幅>0.35 and abs(c-o)/o<0.03 and hc7跌幅>0.03 and ((c-ref(llv(c,7),1))/ref(llv(c,7),1)<0.015) and a2c=1 and v35 and not(除权) and abs(c-o)/o<0.03 and hc60跌幅>0.20 and hc7跌幅>0.06 and (a1c=1 or a2c=1) and v35 and not(除权) and abs(c-o)/o<0.03 and (o+c)/2
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