c++多线程printf重复输出 运行多次，必须是多次，haha会多次输出，qiubai只输出一次，win7，vc6.0

#include <windows.h> //包含头文件
#include <stdio.h>
DWORD WINAPI myfun1( //声明线程函数
LPVOID lpParameter
);
const int stop=1; //stop 为一
const int go_on=2; //开始为2
int record=2;
static HANDLE hmutex;
int a=0; //定义全局变量a
int main()
{

HANDLE h1;
//定义线程句柄

h1=::CreateThread(NULL,0,myfun1,NULL,0,NULL);
printf("haha\n");
//创建线程1

::CloseHandle(h1);
Sleep(1000);//关闭线程句柄对象
return 0;
}
DWORD WINAPI myfun1(LPVOID lpParameter) //线程函数1
{ while(1)
{
::WaitForSingleObject(hmutex,INFINITE); //请求事件对象

//变量自加

a++; //线程睡眠1秒
printf("qiubai\n");
::ReleaseMutex(hmutex);
if(a>0)
break;//释放互斥对象句柄
}

return 0; //线程
}

你应该建立两个进程, 这样才可以观察, 还有你的 haha 是在 main 函数里面, 只执行一次, 不会输出多次, qiubai, 在进程中, 但是 if (a>0) 也就是执行一次之后这个进程虽然没有关闭但是, 已经不可能进入输出的程序了.

#include <windows.h>
#include <stdio.h>
DWORD WINAPI myfun1(LPVOID lpParameter);
DWORD WINAPI myfun2(LPVOID lpParameter);
static HANDLE hmutex, hmutex2;
int main()
{
HANDLE h1;
h1=::CreateThread(NULL,0,myfun1,NULL,0,NULL);
HANDLE h2;
h2=::CreateThread(NULL,0,myfun2,NULL,0,NULL);
printf("Start:\n");
Sleep(5000);
::CloseHandle(h1);
::CloseHandle(h2);
return 0;
}
DWORD WINAPI myfun1(LPVOID lpParameter)
{
int a = 0;
while (1)
{
::WaitForSingleObject(hmutex,INFINITE);
a++;
printf("qiubai\n");
::ReleaseMutex(hmutex);
Sleep(200);
if(a > 15)
break;
}
return 0;
}
DWORD WINAPI myfun2(LPVOID lpParameter)
{
int b = 0;
while (1)
{
::WaitForSingleObject(hmutex2,INFINITE);
b++;
printf("haha\n");
::ReleaseMutex(hmutex2);
Sleep(300);
if(b > 10)
break;
}
return 0;
}