java.lang.IndexOutOfBoundsException: No group 1

答案:4 悬赏:10

解决时间 2021-02-19 06:22

提问者网友：挣扎重来
2021-02-18 12:47

严重: Servlet.service() for servlet jsp threw exception
java.lang.IndexOutOfBoundsException: No group 1
at java.util.regex.Matcher.group(Matcher.java:470)
at gzbd.picopcs.ClientInfo.getExplorerName(ClientInfo.java:56)
at org.apache.jsp.goStat_jsp._jspService(goStat_jsp.java:165)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:619)

ClientInfo.java第56行的内容如下：
if(matcher.find()) explorerVer = matcher.group(1);

最佳答案

二级知识专家网友：夢想黑洞
2021-02-18 14:13

索引越界了吧
比如String[] a=new String[5]; 你调用了String[10]
List list=new Arraylist();
list.add("123");
list.get(10)
又或者String a="abc"; 你调用了a.substring(0,10)
就是这些问题呗

全部回答

1楼网友：星星坠落
2021-02-18 17:28

if(matcher.find()) explorerVer = matcher.group(0);这样如何？ group()是整个匹配结果。索引从0开始计数，group(0)是第一个匹配。

2楼网友：懂得ㄋ、沉默
2021-02-18 17:22

数组越界数组的长度为n 可访问的下标最大值n-1 不能访问下标为n的元素

3楼网友：不羁的心
2021-02-18 15:53

正则只搜索到一个匹配结果，而你调用 group(1)。就不对了、

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