a+1分之a-a的平方-1分之a-2除以a的平方-2a+1分之a的平方-2a
答案:2 悬赏:30
解决时间 2021-02-23 11:52
- 提问者网友：冰点阿弟
- 2021-02-22 12:55
a+1分之a-a的平方-1分之a-2除以a的平方-2a+1分之a的平方-2a
最佳答案
- 二级知识专家网友：伤口狠精致
- 2021-02-22 14:03
原式=[a/(a+1)]-[(a-2)/(a²-1)]÷[(a²-2a)/(a²-2a+1)]
=[a/(a+1)]-[(a-2)/(a²-1)]÷[a(a-2)/(a-1)²]
=[a/(a+1)]-[(a-2)/(a²-1)]×{ (a-1)²/[a(a-2)] }
=[a/(a+1)]- { (a-2)/[(a+1)(a-1)] }×{ (a-1)²/[a(a-2)] }
=[a/(a+1)]-{ (a-1)/[a(a+1)] }
={ a²/[a(a+1)] }-{ (a-1)/[a(a+1)] }
=[a²-(a-1)]/[a(a+1)]
=(a²-a+1)/(a²+a)
=[a/(a+1)]-[(a-2)/(a²-1)]÷[a(a-2)/(a-1)²]
=[a/(a+1)]-[(a-2)/(a²-1)]×{ (a-1)²/[a(a-2)] }
=[a/(a+1)]- { (a-2)/[(a+1)(a-1)] }×{ (a-1)²/[a(a-2)] }
=[a/(a+1)]-{ (a-1)/[a(a+1)] }
={ a²/[a(a+1)] }-{ (a-1)/[a(a+1)] }
=[a²-(a-1)]/[a(a+1)]
=(a²-a+1)/(a²+a)
全部回答
- 1楼网友：茫然不知崩溃
- 2021-02-22 14:54
a^2-2a+1转化为a^2-1是不可能的，哪教出来的，上来就是错的，后边自然没必要往下看了。
2/(a+1)-1÷a/(a²-2a+1)
=(2-a-1)/(a+1)÷a/(a-1)²
=(1-a)/(a+1)x(a-1)²/a
=(1-a)³/(a+1)a
问题已解决记的采纳。
我要举报
如以上问答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
大家都在看
推荐资讯