万年历编程

答案:4 悬赏:20

解决时间 2021-02-19 10:53

提问者网友：你在我眼中是最帅
2021-02-19 00:12

c语言或汇编都可以只要求显示年月日信息可调整日期有可以的我把分全加上最好附原理图

最佳答案

二级知识专家网友：浪女动了心
2021-02-19 01:18

#include
long int f(int year,int month)
{
if(month<3) return year-1;
else return year;
}
long int g(int month)
{
if(month<3) return month+13;
else return month+1;
}

long int n(int year,int month,int day)
{
return 1461L*f(year,month)/4+153L*g(month)/5+day;
}

int w(int year,int month,int day)
{
return(int) ((n(year,month,day)%7-621049L%7+7)%7);
}

int date[12][6][7];
int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};

main()
{
int sw,leap,i,j,k,wd,day;
int year;
char title[]="SUM MON TUE WED THU FRI SAT";

printf("Please input the year whose calendar you want to know:\n");
scanf("%d%*c",&year);

sw=w(year,1,1);
leap=year%4==0&&year%100||year%400==0;
for(i=0;i<12;i++)
for(j=0;j<6;j++)
for(k=0;k<7;k++)
date[i][j][k]=0;
for(i=0;i<12;i++)
for(wd=0,day=1;day<=day_tbl[leap][i];day++)
{
date[i][wd][sw]=day;
sw=++sw%7;
if(sw==0) wd++;
}
printf("\n|================== The Calendar of Year %d==================|\n|",year);
for(i=0;i<6;i++)
{
for(wd=0,k=0;k<7;k++)
wd+=date[i][5][k]+date[i+6][5][k];
wd=wd?6:5;
printf(" %2d %s %2d %s|\n|",i+1,title,i+7,title);
for(j=0;j {
printf(" ");
for(k=0;k<7;k++)
if(date[i][j][k])
printf("%4d",date[i][j][k]);
else printf(" ");
printf(" ");
for(k=0;k<7;k++)
if(date[i+6][j][k])
printf("%4d",date[i+6][j][k]);
else printf(" ");
printf("|\n|");
}
}
puts("==============================================================|");
}

全部回答

1楼网友：白日梦制造商
2021-02-19 05:01

#include void PrintMonthCalender(int startDay,int days); int GetWeekDay(int year,int month); int GetMonthDays(int year,int month); main() { int month,year; printf("input the year and month:"); scanf("%d-%d",&year,&month); printf("\t\t\t%d-%d\n",year,month); printf("Sun.\tMon.\tTue.\tWed.\tThu.\tFri.\tSat.\n"); PrintMonthCalender(GetWeekDay(year,month),GetMonthDays(year,month)); return 0; } void PrintMonthCalender(int startDay,int days) { int k=0,n=1; while(k

2楼网友：迷人小乖乖
2021-02-19 03:35

#include #include #include long year; int month,day,error_input; char s[100]; int monthdays[12]={31,28,31,30,31,30,31,31,30,31,30,31}; void inputdate(){ long n[3]={0,0,0},k=0,i,len; error_input=-1; printf("Please input the year[,month[,day]]:(Enter Q to quit)\n"); gets(s); len=strlen(s); printf("%d\n",strcmp(s,"Q")); if(strcmp(s,"Q")==0) {error_input=0;return;} if(!isdigit(s[0])||!isdigit(s[len-1])) {error_input=1;return;} for(i=0;i2) {error_input=1;return;}} else n[k]=n[k]*10+s[i]-48; } year=n[0]; if(!(year%4)&&(year%100)||!(year%400)) monthdays[1]=29; else monthdays[1]=28; if(n[1]>12) {error_input=1;return;} if(n[2]>monthdays[n[1]-1]) {error_input=1;return;} month=n[1]; day=n[2]; } void printCala(){ int countyear,countday=0,weekflag,i,j,k,c; int startmon,endmon,year1; year1=year-1; countyear=(year1-year1%4)/4-(year1-year1%100)/100+(year1-year1%400)/400; weekflag=(countyear*366+(year-1-countyear)*365+1)%7-1; if(month==0) {startmon=1;endmon=12;} else {startmon=month;endmon=month;} for(k=1;k0&&countday%7==0) printf("\n"); printf("%3d ",i); countday++;} weekflag=(weekflag+monthdays[k-1])%7; printf("\n___________________________\n"); } } int main() { inputdate(); while(error_input!=0) { if(error_input==1) printf("Input ERROR! Please input again:\n"); else printCala(); inputdate(); } }

3楼网友：厭世為王
2021-02-19 02:32

//万年历程序 //wnl.c chinanetboy //test pass with dev-c++4.9.9.2. #include #include #include // all struct,array lists int lunar_info[]={0x04bd8,0x04ae0,0x0a570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2, 0x04ae0,0x0a5b6,0x0a4d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0x0ada2,0x095b0,0x14977, 0x04970,0x0a4b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970, 0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950, 0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0x0a950,0x0b557, 0x06ca0,0x0b550,0x15355,0x04da0,0x0a5d0,0x14573,0x052d0,0x0a9a8,0x0e950,0x06aa0, 0x0aea6,0x0ab50,0x04b60,0x0aae4,0x0a570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0, 0x096d0,0x04dd5,0x04ad0,0x0a4d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6, 0x095b0,0x049b0,0x0a974,0x0a4b0,0x0b27a,0x06a50,0x06d40,0x0af46,0x0ab60,0x09570, 0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0x0ab60,0x096d5,0x092e0, 0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0x0abb7,0x025d0,0x092d0,0x0cab5, 0x0a950,0x0b4a0,0x0baa4,0x0ad50,0x055d9,0x04ba0,0x0a5b0,0x15176,0x052b0,0x0a930, 0x07954,0x06aa0,0x0ad50,0x05b52,0x04b60,0x0a6e6,0x0a4e0,0x0d260,0x0ea65,0x0d530, 0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,0x0a4d0,0x1d0b6,0x0d250,0x0d520,0x0dd45, 0x0b5a0,0x056d0,0x055b2,0x049b0,0x0a577,0x0a4b0,0x0aa50,0x1b255,0x06d20,0x0ada0}; char gan[10][3] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; char zhi[12][3] = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"}; char shu[12][3] = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; char solar_term[24][5] = {"小寒","大寒","立春","雨水","惊蛰","春分", "清明","谷雨","立夏","小满","芒种","夏至", "小暑","大暑","立秋","处暑","白露","秋分", "寒露","霜降","立冬","小雪","大雪","冬至"}; char chinese_num[30][5] = {"初一","初二","初三","初四","初五","初六","初七", "初八","初九","初十","十一","十二","十三","十四", "十五","十六","十七","十八","十九","廿十","廿一", "廿二","廿三","廿四","廿五","廿六","廿七","廿八", "廿九","三十"}; char chinese_month[12][5] = {"一","二","三","四","五","六","七","八","九","十", "十一","十二"}; typedef struct{ int lunar_year; int lunar_month; int lunar_day; int lunar_mday; int leap_month; int leap_state; }lunar_info; typedef struct{ int chinese_era_year; int chinese_era_month; int chinese_era_day; }chinese_era; int s_year,s_month,s_day,week,l_year,l_month,l_day; int s_month_total_day; int l_month_total_day; int l_year_total_day; int l_leap_month; int l_leap_month_day; int space_num; int c_num; int i,j; char tmp_str[9]; chinese_era c_ear; lunar_info l_info; //funcation list int get_solar_total_day(int solar_year, int solar_month) { int total_day; int temp_num; total_day = 0; for (temp_num = 1900; temp_num < solar_year; temp_num++) { if ((((temp_num % 4) == 0) && ((temp_num % 100) != 0)) || (temp_num % 400 == 0)) { total_day += 366; } else { total_day += 365; } } for(temp_num = 1;temp_num < solar_month; temp_num++) { switch(temp_num) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: total_day += 31; break; case 2: if ((((solar_year % 4) == 0) && ((solar_year % 100) != 0)) || (solar_year % 400 == 0)) { total_day += 29; } else { total_day += 28; } break; case 4: case 6: case 9: case 11: total_day += 30; break; } } return total_day; }

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