(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3，y=1/3
答案:2 悬赏:80
解决时间 2021-11-25 05:31
- 提问者网友：夕夏残阳落幕
- 2021-11-24 08:09
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3，y=1/3
最佳答案
- 二级知识专家网友：寂寞的炫耀
- 2021-11-24 09:17
答：
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)
=x^2-y^2+x^2-2xy+y^2-(3x^2-xy)
=2x^2-2xy-3x^2+xy
=-x^2-xy
=-x(x+y)
=-(-3)*(-3+1/3)
=-9+1
=-8
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)
=x^2-y^2+x^2-2xy+y^2-(3x^2-xy)
=2x^2-2xy-3x^2+xy
=-x^2-xy
=-x(x+y)
=-(-3)*(-3+1/3)
=-9+1
=-8
全部回答
- 1楼网友：狠傷凤凰
- 2021-11-24 10:22
(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/(2y) =x^2-y^2-y^2+x^2+y^2-2xy-3x^2+xy =-x^2-y^2-xy =-(x^2+y^2+xy-3xy+3xy) =-(x-y)^2-3xy =-9+6 =-3
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