(x+1)(x的平方+1)(x-1)(x的4次方+1)
答案:5 悬赏:60
解决时间 2021-01-31 11:09
- 提问者网友：刺鸟
- 2021-01-30 15:00
(x+1)(x的平方+1)(x-1)(x的4次方+1)
最佳答案
- 二级知识专家网友：酒安江南
- 2021-01-30 16:06
(x+1)(x的平方+1)(x-1)(x的4次方+1)
=(x-1)(x+1)(x的平方+1)(x的4次方+1)
=(x²-1)(x²+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
即x的8次方-1
=(x-1)(x+1)(x的平方+1)(x的4次方+1)
=(x²-1)(x²+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
即x的8次方-1
全部回答
- 1楼网友：神也偏爱
- 2021-01-30 19:28
x的八次方。先算(x+1)(x-1)得x的平方-1，然后（x的平方+1）乘以（x的平方-1）得（x的四次方-1）再用（x的四次方-1）乘以（x的四次方+1）得x的八次方。
- 2楼网友：山有枢
- 2021-01-30 18:22
(x+1)( x^2+1)(x-1)( x^4+1)= (x+1) (x-1) (x^2+1) (x^4+1)= (x^2-1) (x^2+1) (x^4+1)= (x^4-1) (x^4+1)= (x^8-1)
- 3楼网友：山有枢
- 2021-01-30 16:50
(x+1)(x^2+1)(x-1)(x^4+1)
=(x+1)(x-1)(x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
=(x+1)(x-1)(x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
- 4楼网友：迟山
- 2021-01-30 16:42
(x+1)(x^2+1)(x-1)(x^4+1)
=[(x+1)(x-1)](x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
=[(x+1)(x-1)](x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
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