C语言编程：采用switch语句编写成绩等级：100-90分为A，75-89为B，65-74为C，60-64为D，小于60为E

100-90分为A，75-89为B，65-74为C，60-64为D，小于60为E，用switch语句实现，则程序代码怎么书写？

【俊狼猎英】团队为您解答~
只要分好组就好了吧，用除以5得到的商作为变量
int x,score;
x=score/5;
switch(x){
case 0:
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
case 7:
case 8:
case 9:
case 10:
case 11:
printf("F");
break;
以下类推就好了，总共要写21个case

#include <stdio.h> int main () { int n; char c; scanf("%d",&n); switch (n / 10) { case 10: c = 'A'; break; case 9: c = 'A'; break; case 8: c = 'B'; break; case 7: if (n > 74) c = 'B'; else c = 'C'; break; case 6: if (n > 64) c = 'C'; else c = 'D'; break; default: c = 'E'; break; } printf("%c\n",c); return 0; }

#include<stdio.h> main() { int x; char y; retry: printf("请输入成绩：\n"); scanf("%d",&x); if(x<0||x>100) {printf("成绩输入错误\n"); goto retry; } switch(x/5) { case 12: y='D';break; case 13: case 14: y='C';break; case 15: case 16: case 17: y='B';break; case 18: case 19: case 20: y='A';break; default :y='E';break; } printf("%d分的等级为%c.\n",x,y); } //成功运行

int ndiv = score / 10; switch(ndiv) { case 10: case 9: a; break; case 8: b break case 7: { if(score%10 >=5) b: else c; break; } case 6: { if(score%10 >= 5) c: else d; break } default: e; break; }