x3-2x+1用拆项添项法怎么算
答案:1 悬赏:10
解决时间 2021-03-12 16:27
- 提问者网友：战魂
- 2021-03-12 00:18
x3-2x+1用拆项添项法怎么算
最佳答案
- 二级知识专家网友：夜余生
- 2021-03-12 00:28
x³-2x+1
=x³-x²+x²-x-x+1
=x²(x-1)+x(x-1)-(x-1)
=(x-1)(x²+x-1)
=(x-1)(x²+x+¼ -5/4)
=(x-1)[(x+½)² -5/4]
=(x-1)[x+(1+√5)/2][x+(1-√5)/2]
=x³-x²+x²-x-x+1
=x²(x-1)+x(x-1)-(x-1)
=(x-1)(x²+x-1)
=(x-1)(x²+x+¼ -5/4)
=(x-1)[(x+½)² -5/4]
=(x-1)[x+(1+√5)/2][x+(1-√5)/2]
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