化简[(x²-2x+1/x²-1)+1/x]除以1/x+1
答案:3 悬赏:40
解决时间 2021-02-16 18:09
- 提问者网友：余味
- 2021-02-16 08:58
化简[(x²-2x+1/x²-1)+1/x]除以1/x+1
最佳答案
- 二级知识专家网友：陪我到地狱流浪
- 2021-02-16 09:45
=[(x-1)²/(x+1)(x-1)+1/x]×(x+1)
=[(x-1)/(x+1)+1/x]×(x+1)
=[x(x-1)+(x+1)]/x(x+1)×(x+1)
=(x²-x+x+1)/x
=(x²+1)/x
=[(x-1)/(x+1)+1/x]×(x+1)
=[x(x-1)+(x+1)]/x(x+1)×(x+1)
=(x²-x+x+1)/x
=(x²+1)/x
全部回答
- 1楼网友：一个很哇塞的汉子
- 2021-02-16 11:43
(x²-1)除以(x+1)-根号x²-2x+1=（x+1)(x-1)/(x+1)-√（x-1)²
=x-1-lx-1l
（1）当x≥1时，该式=0；
（2）当x＜1时，该式=x-1-(1-x)=2x-2
- 2楼网友：請叫我丶偏執狂
- 2021-02-16 10:29
[(x²-2x+1)/(x²-1)+1/x]/(1/x+1)
=[(x-1)/(x+1)+1/x]/(1/x+1)
=[1-2/(x+1)+1/x]/(1/x+1)
=1-[2/(x+1)]/(1/x+1)
=1-2x/(x+1)²
=(x²+1)/(x+1)²
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